Volume of a Solid using Triple Integrals

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SUMMARY

The volume of the solid enclosed by the cylinder defined by the equation z = y² and the planes x = 0, x = 6, and z = 16 is calculated using a triple integral. The integration region is defined as D = { (x,y,z) | 0 < x < 6, -4 < y < 4, y² < z < 16 }. The final computed volume is 512 cubic units, confirming the setup and calculations are accurate as validated by peer review in the discussion.

PREREQUISITES
  • Understanding of triple integrals in calculus
  • Familiarity with cylindrical coordinates
  • Knowledge of the equations of planes and surfaces
  • Basic arithmetic and integration techniques
NEXT STEPS
  • Study the application of cylindrical coordinates in triple integrals
  • Explore the use of triple integrals to find volumes of other solids
  • Learn about the divergence theorem and its applications
  • Practice solving triple integrals with varying limits of integration
USEFUL FOR

Students studying multivariable calculus, educators teaching integration techniques, and anyone interested in applying triple integrals to calculate volumes of solids.

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Homework Statement



Use a triple integral to find the volume of the solid enclosed by the cylinder z=y2 and the planes x=0, x=6, and z=16. Set up the integral in rectangular coordinates and work it out in any coordinates.

Homework Equations


The Attempt at a Solution



I set up the triple integral using these orders of integration:

D = { (x,y,z) | 0 < x < 6, -4 < y < 4, y2 < z < 16 }

And I obtained an answer of 512. I just wanted to make sure that I did all the work correctly, and that someone more experienced could say if it is correct.
Thank you!
 
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Your limits look good so if you didn't make any arithmetic mistakes it should be correct.
 
LCKurtz said:
Your limits look good so if you didn't make any arithmetic mistakes it should be correct.
Thank you very much, Mr Kurtz!
 

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