(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A Sample of gas 250 mL at 37 C and 730 torr . What volume would gas occupy at standard conditions ?

2. Relevant equations

pv = nRT

V2 = T2P1V1

-------

T1P2

3. The attempt at a solution

Sample Gas

V = 250 mL ( 0.250 L )

P = 730 torr ( .960 atm )

T = 310 K

Standard Condition

T = 273

V = 22.4 L

P = 1 atm

I'm confused because sample gas formula is already given and then find the gas under stand condition ?

Do I just use standard condition formula and drop the other ones ?

If I use pv = nRT then I get following

v = (0.250 L / 22.4 L = .0111 mol) since STP 1 mol = 22.4 L

p = .960 atm

R = 0.08260 ( constant gas )

T = 310 K

v = (.0111 mol ) (0.08260)(310)

--------------------------

.960 atm

Answer = .290 L

The answer doesn't seem to make sense. Any correction ?

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# Homework Help: Volume of Gas At Standard Condition ? Which Gas Law ?

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