MHB Volumes by Cylindrical Shells (Calculus II)

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The discussion focuses on calculating the volume of a solid formed by rotating the region between the curves y = x and y = x^2 around the y-axis using the method of cylindrical shells. The integral setup presented is correct, expressed as ∫^1_0 (2πx)(x - x^2) dx. The term 2πx represents the circumference of the cylindrical shell, while (x - x^2) indicates the height of the shell. The participants confirm the validity of the integral setup for this calculus problem. Understanding these components is crucial for accurately applying the cylindrical shells method in volume calculations.
shamieh
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Quick question, may seem rather dumb - but I just want to make sure of something..

Question: Find the volume of the solid obtained by rotating about the y-axis the region between y = x and y = x^2

so when I am setting up my integral am I correct in saying $$TOP - BOTTOM i.e. --> \int^1_0 (2\pi x) (x - x^2) dx$$?
 
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Re: Volumes by Cyllindrical Shells (Calculus II)

It looks good to me. The $2\pi x$ gives you the length of a shell, were you to straighten it out. The $x-x^{2}$ gives you the height of a shell, and the $dx$ gives you the thickness.
 

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