Water droplet problem/electric fields

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To determine the number of excess electron charges on a stationary water droplet with a radius of 0.0200 mm in a downward electric field of 150 N/C, the upward electric force must balance the downward gravitational force. The gravitational force can be calculated using the droplet's volume and the density of water, while the electric force is derived from the electric field and the charge on the droplet. By equating these two forces, the required charge can be calculated. The final result will indicate how many excess electrons are present on the droplet to maintain its stationary position in the electric field. This problem illustrates the relationship between electric fields, forces, and charge in a practical scenario.
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We just went over electric fields in class and I need help starting a problem:

A water droplet is stationary and has radius 0.0200mm. The Electric field where the droplet is located in is 150 N/C downward. How many excess electron charges must the water droplet have?
 
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One clue is simply look at the units for electric field. The upward force from the field on the charges must balance the downward force from gravity.
 
It may be shown from the equations of electromagnetism, by James Clerk Maxwell in the 1860’s, that the speed of light in the vacuum of free space is related to electric permittivity (ϵ) and magnetic permeability (μ) by the equation: c=1/√( μ ϵ ) . This value is a constant for the vacuum of free space and is independent of the motion of the observer. It was this fact, in part, that led Albert Einstein to Special Relativity.
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