- #1
Adesh
- 735
- 191
Electric currents and the things within are generally explained through the help of intuitive water current examples, where potential difference is explained through the pressure difference and electric current is explained as the flow of water. But I like to think in terms of some driving force instead of pressure differences, beacuse it seems more intuitive to me that force causes the motion. So, I’m water current example, I won’t think in terms of “uphill” and “downhill” but in terms of “force acting per unit of fluid” and hence fluid will move in the direction of net force.
So, my question is how electric field is caused and distributed inside the wire such that electrons flow all the way from negative terminal to the positive terminal. See this diagram:
Blue plate is positively charged and yellow plate is negatively charged, therefore we have straight field lines (ignoring the boundary lines) going from positive plate to the negative plate. All the red segments are conducting wires.
I agree that field lines will push the electrons from C to A and similarly from B to F, but how free electrons of our conducting wire will move from F to E to D and to C. Because for a part of the segment CD and FE the electric field is perpendicular to the movable path of electrons, and for the other part there is no field. Segment ED lies completely out of the field. So, electrons will move all the way through the circuit? Who will push them?
I hope I made myself clear. Please do give your valuable explanation and knowledge.
So, my question is how electric field is caused and distributed inside the wire such that electrons flow all the way from negative terminal to the positive terminal. See this diagram:
Blue plate is positively charged and yellow plate is negatively charged, therefore we have straight field lines (ignoring the boundary lines) going from positive plate to the negative plate. All the red segments are conducting wires.
I agree that field lines will push the electrons from C to A and similarly from B to F, but how free electrons of our conducting wire will move from F to E to D and to C. Because for a part of the segment CD and FE the electric field is perpendicular to the movable path of electrons, and for the other part there is no field. Segment ED lies completely out of the field. So, electrons will move all the way through the circuit? Who will push them?
I hope I made myself clear. Please do give your valuable explanation and knowledge.