Wave Equation Spherical Perturbations

fluidistic
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Homework Statement


Show that u(r,t)=\frac{f(r-vt)}{r} is a solution to the tridimensional wave equation. Show that it corresponds to a spherical perturbation centered at the origin and going away from it with velocity v. Assume that f is twice differentiable.

Homework Equations



The wave equation: \frac{\partial ^2 u }{\partial t ^2}- c^2 \triangle u =0.

The Attempt at a Solution


I just used the wave equation and found out that \frac{\partial ^2 u}{\partial t^2} = v^2 u''.
While \triangle u =\frac{1}{r} \left [ u''+ \frac{u}{r^2} - \frac{2u'}{r} \right ].
So the wave equation is satisfied if u'' \left ( v^2-\frac{c^2}{r} \right ) + \frac{2 c^2 u'}{r^2} - \frac{u c^2}{r^3}=0.
It's likely wrong so either I set up badly the problem, either I set it up OK but made some errors.
 
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fluidistic said:
While \triangle u =\frac{1}{r} \left [ u''+ \frac{u}{r^2} - \frac{2u'}{r} \right ].
I think that's your problem. Where did you get this expression for the Laplacian?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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