- #1

hdp12

- 68

- 2

I have an online homework question and my classmate told me the answer but I would really like someone to explain to me how that answer was determined. I do not understand. Q: Consider the electric field observed at a point O that is far from the two slits, say at a distance r from the midpoint of the segment connecting the slits, at an angle θ from the

The critical point is that the distances from the slits to point O are not equal; hence the waves will be out of phase due to the longer distance traveled by the wave from one slit relative to the other. Calculate the phase Φ

EQUATIONS:

E(x,t)=E

Φ(x,t)=kx−ωt

ω=2πf

k=2π/λ

SOLUTION:

Φ

I just really don't understand how that is derived...

can someone please help explain?

*x*axis. Here, far means that r≫d, a regime sometimes called*Fraunhofer diffraction*.The critical point is that the distances from the slits to point O are not equal; hence the waves will be out of phase due to the longer distance traveled by the wave from one slit relative to the other. Calculate the phase Φ

_{lower}(O,t) of the wave from the*lower*slit that arrives at point O.EQUATIONS:

E(x,t)=E

_{left}cos[2π/λ(x−ct)].Φ(x,t)=kx−ωt

ω=2πf

k=2π/λ

SOLUTION:

Φ

_{lower}(O, t) = 2π/λ (r−ct) + π/λ dsin(θ)I just really don't understand how that is derived...

can someone please help explain?