An incident light shines on a mercury metal plate with a work function of -4.5 eV. The stopping voltage is observed to be -1.65 volts. What is the wavelenght of the incident light?
wavelength=hc/E-0(it's a Greek sign n i don't have it in my computer)
The Attempt at a Solution
(4.14 X 10^-15 eVs) (3 X 10^8 m/s) / 1.65 + 4.5 = 1.242 X 10^-6 / 6.15
1.242(10^2)/6.15 = 20.1954
but the right answer is 201.7561 nm
so can anyone please tell me what did I do wrong?