Wavelength of light changing in a medium

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Light changes its wavelength when it enters a different medium due to a change in speed, while its frequency remains constant. The speed of light is always c in a vacuum, but it slows down in materials with different refractive indices, leading to a change in the observed wavelength. The interaction between light and the medium's charged particles is complex and cannot be simplified to mere absorption and re-emission. The index of refraction is defined by the speed of light in the medium, and this affects how light behaves, including phenomena like refraction. The color of light, determined by its frequency, does not change in the medium, meaning that red light remains red even when its wavelength is altered.
  • #31
DanMP said:
Group velocity or phase velocity, as in Wikipedia?
It's phase velocity.

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  • #32
DanMP said:
Group velocity or phase velocity, as in Wikipedia?

Sorry, it is phase velocity. For some stupid reason, I flipped things around.

Ugh. More coffee!

Zz.
 
  • #33
pibcrazy said:
This is slightly on topic but a question I have had. Speed is a property of the medium and frequency is a property of the source. Therefore speed decreases, therefore the wavelength decreases (not frequency). The question I have is, does the light change color in the medium, for instance red light in glass will it be green (roughly)? The confusion I have is wavelength is decreased to the blue-green range but the frequency is still at the red range. Is it red or blue-green inside the glass?
It depends on how you define "colour" of the light. Up to now textbooks made you believe the answer was trivial :smile:
How do you want to define it? Consider the answers they have already written.

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  • #34
DariusP said:
Please explain the refraction part? I thought light slows down because of absorption and emission.

You are confusing the model with the thing being modeled. Light is the thing we're modeling. One model makes use of the absorption/emission process you speak of, but a full understanding of that involves a deep sojourn into quantum mechanics and quantum electrodynamics.

I attended a series of lectures given by an atomic physicist. This was about 25 years ago and he was talking about building an atom trap. He showed us how to do a lot of atomic physics without any use of relativity or quantum mechanics. Or as he put, there's not a single ##c## or ##h## anywhere in any of these equations.

He wasn't concerned with how light refracts, but the model can be used to successfully explain the phenomenon of refraction of light. This is essentially Feynman's argument, if IIRC. But, anyway, you model the medium as a collection of atomic nuclei surrounded by electron clouds. When an electromagnetic wave passes through this medium, the oscillating electromagnetic field causes those electron clouds to oscillate, and it is this interaction that is responsible for the change in the speed of the electromagnetic wave. Note that the wave is the model, and yes it's a model of light, but the model is not the light. This is where phrases like "light is an electromagnetic wave" can be misleading.
 
  • #35
sophiecentaur said:
Wooah there. The Frequency is what determines how your light receptors work. Green stays Green (in case you hadn't noticed when you last looked through a glass of water.)

And even if you're inside the glass of water.
 
  • #36
lightarrow said:
It depends on how you define "colour" of the light. Up to now textbooks made you believe the answer was trivial :smile:

I still believe it to be trivial. Show a kid some different colored objects and tell him that people name this particular color, say, green. Then, when you see that same color somewhere else and at some other time, call it green.

If you want to go deeper find out what's happening inside the kid's body when he sees the color he calls green. That part isn't trivial, but assigning names is trivial.
 
  • #37
Assigning wavelengths to colours is very naughty.
 
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  • #38
Mister T said:
I still believe it to be trivial. Show a kid some different colored objects and tell him that people name this particular color, say, green. Then, when you see that same color somewhere else and at some other time, call it green.
I cannot resist pointing out that I know someone who sees limes and carrots as the same color... wavelengths and frequencies are objective physical phenomena, colors much less comfortably so.
 
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  • #39
Nugatory said:
I cannot resist pointing out that I know someone who sees limes and carrots as the same color... wavelengths and frequencies are objective physical phenomena, colors much less comfortably so.
Colours are a cultural thing that are a common descriptive language that works for most people. The majority of people of one culture will agree, roughly, about the name to give the colour of an object although they may not choose exactly the same paint from a shade card to 'match' that object. The success of modern colour TV systems demonstrates this.
 
  • #40
Mister T said:
I still believe it to be trivial. Show a kid some different colored objects and tell him that people name this particular color, say, green. Then, when you see that same color somewhere else and at some other time, call it green.

If you want to go deeper find out what's happening inside the kid's body when he sees the color he calls green. That part isn't trivial, but assigning names is trivial.
If you, then, define "colour" as the name we give to a specific perception, in addition to what sophiecentaur and Nugatory wtote, we have to say that colour perception is an incredibly complex phenomenon: sometimes you can see coloured spots even on gray surfaces for some instants (positive and negative post-image) or even see an entire complex image variously coloured where there is just a two-colours image, you can constantly see coloured shadows where colours cannot exist at all (coloured shadows phenomenon) or see an object as coloured in red under artificial light and green under the Sun (Alexandrite stone), and a lot of other things. Buy a good book on light and colours and you'll discover an entire new world...

Anyway, that was only the "perception" part. The OP could define "colour" in a different way, more technical, even because this must be the case, if we want, e. g. send the right and precise bits to a printer or to a screen to reproduce the right colours on a picture or on the display.
A more precise question he could ask could be:
a) would a picture change if a film exposed to light were in glass (e. g. ) instead of air? Here we would understand better if in this case the process depends on the light frequency (which is the same, with air or glass) or on the light wavelength, which is different (it's the first);
b) if I used a monochromatic red light source, how would the diffraction pattern in the Young experiment change if all the apparatus would be immersed in, let's say, carbon tetrachloride, instead of air?
And so on.

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  • #41
Nugatory said:
No, the interaction between the oscillating electromagnetic field which is light and the charged particles which make up the atoms of the medium is more complicated than simple absorption and reemission. The simple model is a convenient way of explaining why the speed of light is slower in a medium (I've used it myself) but it breaks down when you want to explain frequency-dependent phenomena such as refraction.
I think it is not a convenient way of explaining why the speed of light in a refractive medium is slower than in vacuum, if it were certain (absortion-re-emition delay) speed would depend on the width of the refractive material that light should cross, but it is not, so it is deeply wrong
 
  • #42
pibcrazy said:
This is slightly on topic but a question I have had. Speed is a property of the medium and frequency is a property of the source. Therefore speed decreases, therefore the wavelength decreases (not frequency). The question I have is, does the light change color in the medium, for instance red light in glass will it be green (roughly)? The confusion I have is wavelength is decreased to the blue-green range but the frequency is still at the red range. Is it red or blue-green inside the glass?
No, color is about perception, when your eye receive an image, an opsin molecule absorves a photon and transmits a signal to the photoreceptor cells, photon absortion is about frequency, frequency is the stimulus that matters at the first stage in color perception (not wavelenght), but after that color perception is a complex world ...and as it was said in this thread frequency is determined by the source (in this case we can suppose light reflected from an object)
 
  • #43
lightarrow said:
a) would a picture change if a film exposed to light were in glass (e. g. ) instead of air?
Good question. If it happened, they would need different photo sensors, depending in the substance they're embedded in. (I'm assuming that the effect would have to be as great as the dispersion which we can measure. Another consequence would be that emission and absorption lines would be offset if the frequency changed between an emitter in one medium and an absorption in another - you would get no absorption of monochromatic light.
lightarrow said:
how would the diffraction pattern in the Young experiment change if all the apparatus would be immersed in, let's say, carbon tetrachloride, instead of air
It would have to change according to the wavelength change. I can't think how it could be otherwise.
 
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  • #44
sophiecentaur said:
a) would a picture change if a film exposed to light were in glass (e. g. ) instead of air?
Good question. If it happened, they would need different photo sensors, depending in the substance they're embedded in. (I'm assuming that the effect would have to be as great as the dispersion which we can measure. Another consequence would be that emission and absorption lines would be offset if the frequency changed between an emitter in one medium and an absorption in another - you would get no absorption of monochromatic light.
For conventional pictures it's light frequency which counts, but what about Lippmann's photography?
https://en.m.wikipedia.org/wiki/Lippmann_plate
Here the image is formed because of the interference between incident an reflected light in the emulsion; what happens if the emulsion's refractive index changes appreciably?
how would the diffraction pattern in the Young experiment change if all the apparatus would be immersed in, let's say, carbon tetrachloride, instead of air?
It would have to change according to the wavelength change. I can't think how it could be otherwise.
Of course :smile:

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  • #45
lightarrow said:
Anyway, that was only the "perception" part. The OP could define "colour" in a different way, more technical, even because this must be the case, if we want, e. g. send the right and precise bits to a printer or to a screen to reproduce the right colours on a picture or on the display.

All of that can be, and probably is, determined empirically. In other words, a more technical definition of color is not required to accomplish this task.

A more precise question he could ask could be:
a) would a picture change if a film exposed to light were in glass (e. g. ) instead of air? Here we would understand better if in this case the process depends on the light frequency (which is the same, with air or glass) or on the light wavelength, which is different (it's the first);

You mean, like, sandwich a piece of film in between two glass plates? Or even embed a CCD in glass. Again, looking at the colors produced in such a manner is trivial. It requires no more precision than looking at a painting on a wall and identifying the colors seen there.

b) if I used a monochromatic red light source, how would the diffraction pattern in the Young experiment change if all the apparatus would be immersed in, let's say, carbon tetrachloride, instead of air?

That's a question about the measurement of physical properties such as wavelength, not about a determination of color.
 
  • #46
Color is a hard concept, you can have two color samples with different spectra (!) (suppose mixing different pigments to get a defined color) that under a D5 Illuminant could offer a perfect match, but when you change the illuminant to C you get an imperfect match between the samples (metamerism). Frequencies are not related in a direct way to perceived colors. To define perceived color from an object seeing by an observer, the observer could have use (e.g) a Munsell Chart in his hand under Illuminant C, doing the match, and obtaining Hue-Value-Chroma coordinates, then he could say "this is the colour I've seen in the scene". When you think in perceived colors you should forget the term "frequency", just because the distant stimulus is the Radiant Spectra, if you are looking at a lemon, the green-yellow color you perceived is formed (the distant stimulus) by the contribution (amplitude) of every frequency in the passband filter that our Human Vision System can manage, and this is only the zero-stage in color perception ...
 
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  • #47
+1
 
  • #48
Mister T said:
All of that can be, and probably is, determined empirically. In other words, a more technical definition of color is not required to accomplish this task.
You mean, like, sandwich a piece of film in between two glass plates? Or even embed a CCD in glass. Again, looking at the colors produced in such a manner is trivial. It requires no more precision than looking at a painting on a wall and identifying the colors seen there.
That's a question about the measurement of physical properties such as wavelength, not about a determination of color.
The colours you see on a Lippmann's photograph depends on light wavelengths or on its frequency? This is just an example to explain the reason I asked the OP to refine his question and the reason I wrote...what I wrote.

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  • #49
lightarrow said:
The colours you see on a Lippmann's photograph depends on light wavelengths or on its frequency?
What would the colours of light produced by a diffraction grating look like if the grating were under water? (Or for an oil film between glass and water etc. etc.)
 
  • #50
lightarrow said:
The colours you see on a Lippmann's photograph depends on light wavelengths or on its frequency? This is just an example to explain the reason I asked the OP to refine his question and the reason I wrote...what I wrote.

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Quoting from Wikipedia "The colour image can only be viewed in the reflection of a diffuse light source from the plate" this is the object that you are looking at (a Lipmann's photograph) : Diffuse light reflected from the plate, the radiant spectra reflected for each pixel will contain lots of frequencies, each of them contributing with its amplitude to the spectra you receive in your retina when you focus the just small region allowed by the angle (about 2º) of your fovea (fovea vision as opposite to peripheral vision), what it is happening inside the film doesn't care, you are receiving light reflected from the plate. The perturbation that means in the electromagnetic field that constitutes the incoming light is the set of frequencies conforming that spectra, imagine each frequency as a metronome the tic-tac is the perturbation, it doesn't matter if the film is under colored water or you as an observer are under colored water, you will perceive that perturbation independent of the media.
Obviously there are other kind of phenomena that depends on wavelength (standing waves, diffraction, etc.) but when you look at an opaque object in a scene under a defined illuminant, you will receive the reflected light coming from that object discarding the contribution of all frequencies lesser than 430 THz (infrared) and greater than 770 THz (ultraviolet) i.e. [430 THz, 770 THz] after that becomes color perception ...
I have supposed an opaque sample that reflects incoming light, but the spectra could be a refracted/reflected/transmitted (e.g. through a film), but when it leaves the sample is just a pack of information called spectra traveling directly to your retina
 
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  • #51
sophiecentaur said:
What would the colours of light produced by a diffraction grating look like if the grating were under water? (Or for an oil film between glass and water etc. etc.)
No, I was referring to the interference pattern, not to the perception of the colour, as I wrote before.
We know that

d⋅sin(α) = n⋅λ

and λ will be different so the pattern will be too. If, for a specific value of n, we measure α, we find a different λ. Let' say that the difference between the two lambdas is too small to be appreciated by the human eye even if the frequencies were different and you don't know if the difference in wavelength is due to a difference in the source's frequency or to a difference in the medium's refractive index, do you conclude that the colour is "roughly" the same just because it seems the same to you eyes? Your precise measurements tell you the wavelengths are different..
What I mean is that "colour perception" is a thing, a "precise definition of colour" is another and one could define it using wavelengths, as many textbooks do (even if I am not keen on it). So we need a definition...

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  • #52
DanielMB said:
...
but when it leaves the sample is just a pack of information called spectra traveling directly to your retina
Yes and why was the OP referring to the medium between the photograph and the eye and not between the reflecting surface of that photograph and the eye? In theory, a lot of things are included in his generic question, even if what you say is certainly the most obvious.
For this reason I asked the OP for a better specification of its question.

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  • #53
lightarrow said:
No, I was referring to the interference pattern, not to the perception of the colour, as I wrote before.
I think the emphasis of the thread have shifted here and there. If you illuminate a diffraction grating from all directions you may see 'colours' - a mixture of different wavelengths in different parts of the grating. That's what I meant, the same as when you see an oil film or reflections in a CD.
In this thread, the words colour and wavelength, have been used indiscriminately. Combinations of monochromatic and wide spectrum light are perceived as colour and colour is what we actually see. Interference patterns in nature produce colours. The mechanics of this are wavelength dependent. This is particularly relevant to the Lipmann system.
 

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