Webpage title: Calculating Coulombs in a Nickel Coin

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SUMMARY

The calculation of charge in a 5-gram nickel coin results in approximately 2.3 x 105 Coulombs. This conclusion is based on the atomic properties of nickel, which has an atomic number of 28 and an atomic mass of 58.7 u. By determining the number of moles in 5 grams of nickel and multiplying by Avogadro's number (6.022 x 1023 atoms), the total number of electrons is calculated, leading to the final charge conversion to Coulombs.

PREREQUISITES
  • Understanding of atomic structure, specifically nickel's atomic number and mass.
  • Familiarity with mole calculations and Avogadro's number.
  • Basic knowledge of charge and its measurement in Coulombs.
  • Ability to perform unit conversions in scientific calculations.
NEXT STEPS
  • Research the properties of nickel, including its atomic structure and common applications.
  • Learn about Coulomb's law and its implications in electrostatics.
  • Explore advanced topics in electrochemistry related to charge calculations.
  • Study mole concept applications in different chemical contexts.
USEFUL FOR

Students in chemistry, physicists, and anyone interested in electrostatics and atomic calculations will benefit from this discussion.

leprofece
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How many Coulombs of charge positive and negative are there is a coin of 5 g of mass?
Answe: 2,3.105 C

I don't know but I have no idea I think there is no enough data
 
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Do you know of what metal the coin is made?
 
leprofece said:
How many Coulombs of charge positive and negative are there is a coin of 5 g of mass?
Answe: 2,3.105 C

I don't know but I have no idea I think there is no enough data

If we suppose that the coin is made of nickel, the atomic number is $28$ and the atomic mass is $58.7 \text{ u}$.

Therefore $5 \text{ grams}$ contains $\frac {5}{58.7} \text{ mol}$ in metal atoms.
Multiply by $N_A$ and we find $\frac {5}{58.7} \cdot 6.022\cdot 10^{23}\text{ atoms}$.
With 28 electrons that corresponds to:
$$\frac {5}{58.7} \cdot 6.022\cdot 10^{23} \cdot 28 \text{ electrons}$$
Convert to coulombs and we get:
$$\frac {5}{58.7} \cdot \frac{6.022\cdot 10^{23}}{6.241\cdot 10^{18}}\cdot 28 = 2.3\cdot 10^5 \text{ coulombs}$$

I think the coin is made of nickel! ;)
 
Last edited:

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