- #1
artriant
- 35
- 2
circular cable i mean *
Hey all second time to use this forum, hope to get same awesome help.
Lets say that we have a cable in a shape of a closed perfect circle rotating in perfect conditions no air zero gravity etc around a center.
The cable is 100 m circumference, rotating at 1rpm
My problem is to find out a way to support how much weight i can distribute. But weights can be distributed in different ways(space in between, how many, theoretical or actual shape) . So I am trying to go from a simplified version to a more complex one gradually.
So let's make the simplified version CASE 1:
We equally distribute 10 points of mass around.the cable.
Lets assume wire has zero mass no actuall volume and bend resistance is absent, but preserves other characteristics like it cannot brake easily(can hold 10.000 Kg tensile force with safety).
So since we add more mass on specific points the shape will change, and in equelibrium still we force it on 1 rpm, we are going to end up with a rotating Decagon! with 10 x 144deg interior angles and the r on each point of added mass will be now 16.1803m (previusly r was 15.92m while on perfect circle).
The question is how much mass is allowed on each point, to end up with a safe tensile force (10K kg).
Hey all second time to use this forum, hope to get same awesome help.
Lets say that we have a cable in a shape of a closed perfect circle rotating in perfect conditions no air zero gravity etc around a center.
The cable is 100 m circumference, rotating at 1rpm
My problem is to find out a way to support how much weight i can distribute. But weights can be distributed in different ways(space in between, how many, theoretical or actual shape) . So I am trying to go from a simplified version to a more complex one gradually.
So let's make the simplified version CASE 1:
We equally distribute 10 points of mass around.the cable.
Lets assume wire has zero mass no actuall volume and bend resistance is absent, but preserves other characteristics like it cannot brake easily(can hold 10.000 Kg tensile force with safety).
So since we add more mass on specific points the shape will change, and in equelibrium still we force it on 1 rpm, we are going to end up with a rotating Decagon! with 10 x 144deg interior angles and the r on each point of added mass will be now 16.1803m (previusly r was 15.92m while on perfect circle).
The question is how much mass is allowed on each point, to end up with a safe tensile force (10K kg).