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Andreas C
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I'm sure that I am not the first one to notice this, but I found that for angles between 0 and 90 degrees, tan(90-10^n) approximately equals 5.7296*10^(-n+1). Is that purely a coincidence?
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It almost works for n=1, it works sort of for n=0 and works very well for any negative value of n. I made a mistake, I meant that it equals 5.7*10^(-n+1). Sorry about that.Prem1998 said:Well, that worked for n=1 approximately
in my calculater. Didn't work for n=0. Those two were the only positive values I could try. I can say without calculating that it won't work for negative values of n. Tried n=1.5 but, no. Can you tell that for which values is it working?
Let'sthink said:In general it cannot be true as most values of tan will be irrational and the right side of your hypothesis will give you a rational number for integral values of n!
Sure you didn't mean ##\tan(90° - 10^{-n}) \approx 5.7_3 \cdot 10^{n+1}\; \;(n \in \mathbb{N})\;##?Andreas C said:It almost works for n=1, it works sort of for n=0 and works very well for any negative value of n. I made a mistake, I meant that it equals 5.7*10^(-n+1). Sorry about that.
I don't know if this is a co-incidence but I had noticed the same pattern a few days ago when I was plugging in 89, 89.9, 89.99, 89.999 etc in my calculater to notice the changes in values of tanx. And, every time the same digits appeared that you've written with the decimal point displaced. I ignored it and didn't take the trouble of making a formula. It might be a co-incidence that you're uploading this today.Andreas C said:It almost works for n=1, it works sort of for n=0 and works very well for any negative value of n. I made a mistake, I meant that it equals 5.7*10^(-n+1). Sorry about that.
fresh_42 said:Sure you didn't mean ##\tan(90° - 10^{-n}) \approx 5.7_3 \cdot 10^{n+1}\; \;(n \in \mathbb{N})\;##?
TeethWhitener said:I'm guessing it has something to do with the Taylor series.
$$\tan(\frac{\pi}{2}-\theta) = \cot \theta$$
The Taylor series for cotangent is:
$$\cot \theta = \frac{1}{\theta} - \frac{1}{3}\theta - \frac{1}{45}\theta^3 + \cdots$$
I'm assuming you were working in degrees instead of radians, so we have to convert ##10^n## to radians:
$$\theta = \frac{10^n\pi}{180}$$
Plugging this back in:
$$\cot(\frac{10^n\pi}{180}) = \frac{180}{10^n\pi} - \frac{10^n\pi}{3\times 180} - \cdots$$
For ##n=1##, we have:
$$\cot(\frac{\pi}{18}) \approx \frac{18}{\pi} \approx 5.73$$
Because of the functional form of the series (with a ##1/\theta## term out front), as ##\theta## gets smaller, the first term in the series becomes a better and better approximation.
The Weird Tangent Property is an unusual mathematical phenomenon where the tangent of an integer is equal to the integer itself. It is considered a coincidence because it is not a commonly known property and it is not easily explainable by traditional mathematical principles.
No, the Weird Tangent Property is not a proven mathematical concept. It is simply an observed pattern that has not been formally studied or proven.
As of now, there are no known real-life applications of the Weird Tangent Property. It is mainly a curiosity in the field of mathematics.
There is no evidence to suggest that the Weird Tangent Property can be extended to other trigonometric functions. However, further research and study may reveal new insights into this phenomenon.
Currently, there is no definitive explanation for the Weird Tangent Property. Some theories suggest that it may be related to the periodicity of the tangent function, while others believe it may be a result of random chance.