What am I doing wrong? Thermochemistry

  • Thread starter Thread starter ace123
  • Start date Start date
  • Tags Tags
    Thermochemistry
AI Thread Summary
The discussion revolves around calculating the heat per mole of CO2 produced from the combustion of octane. The user initially calculated -359.5 KJ/mol but found it did not match the provided answer choices. After multiple revisions and using different enthalpy values, the user arrived at approximately -679 KJ/mol, with the closest option being -684 KJ/mol. The conversation highlights the importance of using accurate enthalpy data and suggests that various methods, such as combustion enthalpies, can lead to different results. Ultimately, the user expresses gratitude for the assistance received in resolving the calculation issue.
ace123
Messages
250
Reaction score
0
[SOLVED] What am I doing wrong? Thermochemistry

1. Calculate the heat per mole of CO2 produced for octane.

2. I just balanced the equation and calculated the total heat produced. Subtracted the heat of water produced from it. Then took that and divided it by the number of moles.

2(C8H18) + 5O2====> 16CO2 + 18H20

3. My answer was -359.5 KJ/mol. But that's not one of the choices. So what did I do wrong?
 
Physics news on Phys.org
If you throw in all the enthalpies you used in the calculation, that'll make it much easier to debug any errors.

Also, what are the choices?

PS: Shouldn't that be 25 O2?
 
Last edited:
Yes, it is 25 O2 sorry for that. The enthalpies I used:

octane- -296 KJ
H2O- -286 KJ
CO2- -394 KJ

Their are 9 choices
all in KJ/mol

-400
-1000
-740
-1100
-320
-684
-468
-840
-890
 
Last edited:
Looks to me like it should come out around -610kJ/mol. What data are you expected to use? Bond enthalpies, combustion enthalpies, calorific values...there are many ways to skin the bird.

Edit: that should be -670kJ/mol (approximately) - closest option is -684kJ/mol

Edit2: Found better data; now I get -679kJ/mol
 
Last edited:
How did you do it? I did combustion enthalpies

Edit: I just did it again and i got -690 KJ/mol I have no clue how i kept getting -359:redface:

Edit (part 2): Thank you
 
Last edited:
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...

Similar threads

Back
Top