- #1
cristianbahena
- 16
- 1
In Hartree-Fock method, I saw the Fock operator has two integrals: Coulomb integral and exchange integral. One can define two operator. "The exchange operator is no local operator" why? Whats de diference: local and no local operator?
And why do the operators have singularities?
thanks
And why do the operators have singularities?
thanks