What are the approximations made when applying the wave-equation to light waves?

  • Thread starter Thread starter yetar
  • Start date Start date
  • Tags Tags
    Light Wave
AI Thread Summary
The discussion centers on the behavior of light waves in relation to the wave partial differential equation (PDE) and whether light expands as a 3D sphere or travels in straight lines. It is clarified that photons travel in straight lines, but a laser beam, composed of many photons, does disperse slightly in all directions. The wave equation can be approximated by replacing the second time derivative with -(omega)^2, leading to the Helmholtz equation, which can be further simplified to the Paraxial Wave Equation for beam analysis. This equation predicts that light beams, such as lasers, will diffract and spread in a cone-like manner as they propagate. Overall, the conversation highlights the complexities of modeling light behavior using wave equations.
yetar
Messages
53
Reaction score
0
I was thinking about the wave PDE: Utt-c^2*(Uxx+Uyy+Uzz) = 0
And wanted to see in respect to this PDE what is a source of light or a laser.
My question is, does the light waev front always expands like a 3D sphere? Or is a light wave actually a straight line in the 3D space?
If the first is true, then it means that even when you have a laser, the light of the laser should also expand to all the direction from the laser line. Maybe it will very little, but still it would expand in all the direction.
If the lightwave is just a straight line, then a light source like a flash light is just a lot of straight lines coming out in a lot of directions?
Why did I mention the PDE...
Becaue if we look at: Utt-c^2*(Uxx+Uyy)=0
Then a certain point in (x, y, t) is affected by a cone with its axis vertical to the XY plane.
So even if you have a straight line in XY with width larger then 0 (a laser?) then a point which its XY is not on this line projection on the XY plane, will be affected by it, because the cone will "catch" the line.
Maybe you could clear this to me better.

Thanks in advance.
 
Last edited:
Science news on Phys.org
Photons travel in a straight line. Think of a photon as an intersection of mutually perpendicular electric and magnetic field.

A laser or any other light beam is a 'collection' or group of photons. A group does disperse.
 
There are a couple of approximations we can make when applying the wave-equation to light waves.

Firstly, we can replace the second time derivative with -(omega)^2 since we know the explicit time dependence of a monochromatic wave. The resultant equation is the Helmholtz equation.

http://mathworld.wolfram.com/HelmholtzDifferentialEquation.html

The Helmholtz equation can be further simplified by factoring out the rapid oscillation in E with propagation distance (z), and assuming that the second derivative w.r.t. z is negligibly small (i.e. assuming a beam-type solution). One then obtains the Paraxial Wave Equation.

The Paraxial Wave Equation is the starting point for most forms of beam analysis, with the simplest solution being a Gaussian Beam (sometimes designated the HE00 or LP01 mode). Higher order solutions also exist, based on Hermite or Laguerre polynomials. A basic derivation can be found here;

http://electron9.phys.utk.edu/optics507/modules/m4/gaussian_beams.htm

Gaussian optics predicts that a light beam will diffract (spread) as it propagates, in a cone-like manner. The half-angle of this 'cone' is called the far-field diffraction angle and is derived in the link above.

I hope that satisfies some questions.

Claude.
 
Last edited by a moderator:
Back
Top