What Are the Correct Steps to Determine the Thevenin Equivalent Circuit?

  • Thread starter Thread starter orangeincup
  • Start date Start date
  • Tags Tags
    Equivalent
AI Thread Summary
To determine the Thevenin equivalent circuit, the process involves calculating Rth and Vth using methods like short-circuiting voltage sources and applying node voltage techniques. The discussion highlights confusion around when it's appropriate to ignore certain resistors, particularly in circuits with controlled sources. Participants emphasize that neglecting components like a 10kΩ resistor can lead to incorrect results, suggesting that all relevant resistors must be considered in calculations. The importance of correctly applying circuit analysis methods is reiterated, especially when dealing with complex configurations. Understanding these principles is crucial for accurate Thevenin equivalent calculations.
orangeincup
Messages
121
Reaction score
0

Homework Statement


Find the Thevenin equivalent circuit with respect to terminals a, b


Homework Equations


i1+i2+i3..=0
v1+v2+v3..=0
i=v/R


The Attempt at a Solution


I set a short circuit across 72V, and calculated that Rth is 6Ω. My first question is, how come I can't always do this? I get problems where I have to calculate Rth a completely different way. How can I tell when this is acceptable to do?

Now I'm using the node voltage method to calculate Vth

So I did part of my equation, which is:
(v1-72)/5+v1/20+(v1-Vth)/8=0
(Vth-v1)/8-...
But I'm not sure what I use next
 

Attachments

  • th.png
    th.png
    1.5 KB · Views: 470
Physics news on Phys.org
orangeincup said:
My first question is, how come I can't always do this? I get problems where I have to calculate Rth a completely different way. How can I tell when this is acceptable to do?

Hm ... offhand, I don't remember this ever being an issue unless there is some kind of weird controlled source. Can you give an example of such a problem?
 
  • Like
Likes 1 person
phinds said:
Hm ... offhand, I don't remember this ever being an issue unless there is some kind of weird controlled source. Can you give an example of such a problem?

I meant ones with controlled sources, I don't know how to solve those. Also ones like this.

It works if I pretend the 10kΩ isn't part of the circuit, but I'm not sure why that is...
 

Attachments

  • exa.png
    exa.png
    2 KB · Views: 475
If you pretend that the 10K is not part of the circuit, you cannot possibly get the right Rth, so I suggest your book has a wrong answer or something else is misleading you.
 
orangeincup said:
Now I'm using the node voltage method to calculate Vth

So I did part of my equation, which is:
(v1-72)/5+v1/20+(v1-Vth)/8=0
(Vth-v1)/8-...
But I'm not sure what I use next

You need to include the 12Ω branch for the Vth node equation.
 
  • Like
Likes 1 person
Here's what my book says for Rth, they calculated 12||20 +2.5, and ended up with 5kΩ
 

Attachments

  • rthh.png
    rthh.png
    10.1 KB · Views: 471
Exactly. Why did this make you think they ignored the 10K resistor? They obviously did not
 
Why is it not in the equation though? It is because it's parallel to a zero resistor?
 
orangeincup said:
Why is it not in the equation though? It is because it's parallel to a zero resistor?

Reread post #4. Forget what the book says. Do it right and you'll get the right answer (which is NOT the answer they got, 'cause they didn't do it right).

Why would you think it is parallel with a zero ohm resistor? WHAT zero ohm resistor?
 
Back
Top