What are the equations for calculating equivalent resistance in a circuit?

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Homework Help Overview

The problem involves calculating the equivalent resistance of an infinite circuit of identical resistors. The original poster expresses uncertainty about how to begin the calculation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the concept of adding stages to the circuit and how it affects the equivalent resistance. One participant suggests writing an equation based on the existing resistance and adding another stage, while another raises a question about the sign in the quadratic solution derived from the resistance equation.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations and mathematical approaches. Some guidance has been provided regarding the reasoning behind the infinite nature of the circuit and its implications on resistance. However, there is no explicit consensus on the correct interpretation of the quadratic solution.

Contextual Notes

Participants are navigating forum rules that discourage providing complete solutions, which influences the nature of the discussion. There is also a request for additional resources to aid understanding.

rbwang1225
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Homework Statement


A circuit extends forever to the right, and all the resistors have the same value ##R##. Calculate the equivalent resistance measured across the two terminals at left.
circuit.jpg



Homework Equations


The series and parallel equivalent resistance equation.


The Attempt at a Solution


I have no idea to begin, could someone give some suggestions for me.
Sincerely.
 
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There is a paper on this on the web but if I post a link to it that will give you too much help.

If the chain is infinite then adding another "stage" to the input won't change the resistance because it's equivalent to shifting the whole chain physically one place to the left.

So call the existing resistance Z and write an equation for the resistance with an additional stage added...

Z = Z//R + 2R

Over to you..
 
Last edited:
Dear CWatters:

Could you post the link to me?
I want to understand it more clearly.

Regards
 
The forum rules discourage us giving away the whole solution so before I do that which bit are you struggling with?

Here is a diagram explaning of why adding a stage doesn't change the resistance. It works because ∞ + 1 = ∞.

Although you are adding a stage to the left the result is indistinguishable from adding a stage to the right hand side which is at infinity.
 

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Here is how you derive the equation for Z that you need to solve...
 

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I think I understand the argument, so the equations are as follows:
##Z=Z//R+2R=(\frac{1}{Z}+\frac{1}{R})^{-1}+2R=(\frac{R+Z}{RZ})^{-1}+2R=\frac{ZR}{Z+R}+2R##
##ZR+Z^2=ZR+2R^2+2ZR##
##Z^2-2RZ-2R^2=0##
##Z=\frac{2R±√(4R^2+8R^2)}{2}=(1±√3)R##
There is a problem for choosing the sign.
Is there any argument that one of which is right?
If my calculations are correct, could you please let me see the paper?
Thank you for kind reply!
 
I think that Z should be positive, therefore, ##Z=(1+\sqrt 3)R##.
 
Dear CWatters:

Thank you for kind help!

Regards.
 

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