What Are the Identities of M and M2S3 When M Reacts with Sulfur to Form M2S3?

  • Thread starter Thread starter triplepie
  • Start date Start date
  • Tags Tags
    Formula
AI Thread Summary
The discussion centers on identifying the metal M and the compound M2S3 formed when M reacts with sulfur. Given that 3.12g of M reacts with 2.88g of sulfur, participants calculate the moles of sulfur, which amounts to 0.09 moles. The next step involves determining the moles of metal M and its molar mass to identify both M and M2S3. The conversation highlights the challenge of deriving the molar mass of the unknown metal based on the provided weights. Ultimately, the goal is to establish the identities of M and M2S3 through stoichiometric calculations.
triplepie
Messages
15
Reaction score
0
1. An unknown metam M reacts with sulfur to form a compound with the formula M2S3. If 3.12g of M reacts with 2.88g of S, what re the names of M and M2S3?



2. 2.88g S ( 1 mol of S/ 32.07 g S) = 0.09 mol of S, that's all i can think of really.



3. Haven't been able to get one.
 
Physics news on Phys.org
0.09 moles of S, how many moles of metal?

What is the metal molar mass?

--
methods
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top