What Are the Implications of Choosing Different Paths in Entropy Calculations?

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Discussion Overview

The discussion revolves around the implications of choosing different paths in entropy calculations, particularly in the context of Clausius' theorem. Participants explore the conditions under which entropy differences are calculated for reversible and irreversible processes, examining potential contradictions that arise from different path selections.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the validity of using the path ##R-P## as a closed cycle, suggesting it leads to contradictions in the entropy equations derived from Clausius' theorem.
  • Another participant clarifies that the inequality involving the path ##P## must account for its irreversibility, indicating that ##-\int_{-P} \frac{dQ}{T} \neq \int_{P} \frac{dQ}{T}##.
  • A participant emphasizes that for irreversible paths, the forward and reverse processes cannot be made identical, noting that spontaneous processes do not allow for a simple reversal.

Areas of Agreement / Disagreement

Participants express differing views on the implications of choosing paths in entropy calculations, with no consensus reached on the restrictions of using closed cycles in Clausius' theorem.

Contextual Notes

There are unresolved questions regarding the assumptions made when selecting paths for entropy calculations, particularly concerning the nature of irreversible processes and their implications for the application of Clausius' theorem.

Haorong Wu
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TL;DR
Are there any restrictions of choosing circles in Clausius theorem?
Hi, I am currently reading Introduction to statistical physics by Huang. In the section of entropy, it reads

Let ##P## be an arbitrary path from ##A## to ##B##, reversible or not. Let ##R## be a reversible path with the same endpoints. Then the combined process ##P-R## is a closed cycle, and therefore by Clausius' theorem ##\int_{P-R} dQ/T \leq 0##, or
##\int_{P} \frac {dQ} {T} \leq \int_{R} \frac {dQ} {T}##.
Since the right side is the definition of the entropy difference between the final state ##B## and the initial state ##A##, we have ##S \left ( B \right ) - S \left ( A \right ) \geq \int_{A}^{B} \frac {dQ} {T}## where the equality holds if the process is reversible.

But what if I choose ##R-P## as a closed cycle? Then in a similar process, I should have ##\int_{R} \frac {dQ} {T} \leq \int_{P} \frac {dQ} {T}## and ##S \left ( B \right ) - S \left ( A \right ) \leq \int_{A}^{B} \frac {dQ} {T}##, which are contradicted to the equations above. I am not sure what goes wrong. Maybe there are some restrictions when I choose a closed cycle, but I did not find any relevant context in the book.
 
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In your setting you should have
\int_R \frac{dQ}{T} \leq -\int_{-P}\frac{dQ}{T} where
-\int_{-P} \frac{dQ}{T} \neq \int_{P}\frac{dQ}{T}
because P is not a reversible process.
 
anuttarasammyak said:
In your setting you should have
\int_R \frac{dQ}{T} \leq -\int_{-P}\frac{dQ}{T} where
-\int_{-P} \frac{dQ}{T} \neq \int_{P}\frac{dQ}{T}
because P is not a reversible process.

Thanks, anuttarasammyak. I understand it now.
 
Haorong Wu said:
Summary:: Are there any restrictions of choosing circles in Clausius theorem?

Hi, I am currently reading Introduction to statistical physics by Huang. In the section of entropy, it reads
But what if I choose ##R-P## as a closed cycle? Then in a similar process, I should have ##\int_{R} \frac {dQ} {T} \leq \int_{P} \frac {dQ} {T}## and ##S \left ( B \right ) - S \left ( A \right ) \leq \int_{A}^{B} \frac {dQ} {T}##, which are contradicted to the equations above. I am not sure what goes wrong. Maybe there are some restrictions when I choose a closed cycle, but I did not find any relevant context in the book.
For the irreversible paths, P can't be made the same for any opposite path and for the forward path. If it happens spontaneously for the forward path, it will not be spontaneous for the reverse path, and you can't even force it to follow the exact reverse path.
 
Chestermiller said:
For the irreversible paths, P can't be made the same for any opposite path and for the forward path. If it happens spontaneously for the forward path, it will not be spontaneous for the reverse path, and you can't even force it to follow the exact reverse path.

Thanks, Chestermiller. I just start learning statistical physics, and thanks for pointing this important point for me.
 

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