What are the limits of integration for evaluating a double integral?

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SUMMARY

The discussion focuses on evaluating the double integral ∫ ∫ R sin(x/y) dA, where R is bounded by the y-axis, y=π, and x=y². The correct limits of integration are confirmed as ∫₀^π ∫₀^(y²) dy dx. Participants emphasize the importance of treating one variable as constant during integration, which is crucial for correctly evaluating the integral of sin(x/y).

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  • Understanding of double integrals in calculus
  • Familiarity with the concept of limits of integration
  • Knowledge of trigonometric functions and their integrals
  • Experience with variable substitution in integration
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  • Practice evaluating double integrals with varying limits of integration
  • Learn about the properties of trigonometric integrals, specifically sin(x/y)
  • Explore techniques for changing the order of integration in double integrals
  • Study the application of variable substitution in complex integrals
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ilovemath88
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Homework Statement



Evaluate the following double integral:
∫ ∫ R sin (x/y) dA

where R is the region bounded by the y axis, y=pi and x=y^2

Homework Equations



as in problem statement

The Attempt at a Solution



Well I started this question by drawing the area to be evaluated. From this I chose my limits of integration, however I feel this may be where I am going wrong. I used ∫ (upper y=pi lower y=0) dy and ∫ (upper x=y^2 lower x=0) dx.
Im not sure if this is right first of all, and secondly, sin (x/y) is really tripping me up. This is because when I treat a variable as constant, where is it going. For example if I firstly evaluate sin (x/y) dy, I'm not sure of the result.
 
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Hi ilovemath88! Welcome to PF :smile:

(have an integral: ∫ and a pi: π and try using the X2 and X2 tags just above the Reply box :wink:)

Yes, your limits, ∫0π0y2 are correct.

As you say, you have to treat one variable as a constant when you integrate wrt the other …

so which is easier to integrate first, sin(x/y)dx or sin(x/y)dy ? :wink:
 

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