What are the minimum and maximum values of theta for the moment equation?

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The discussion focuses on determining the angles theta that yield maximum and minimum moments about point A due to a 70N force acting on a pipe. The moment equation derived is M = (70cosθ * 0.9) + (70sinθ * 0.7), with its derivative being -63sinθ + 49cosθ. The user initially finds only one critical point corresponding to the maximum moment, leading to confusion about identifying the minimum value of theta. It is clarified that at 0º, the moment is positive and increases until reaching a maximum at tanθ = 7/9, after which it decreases to a minimum at 180º. Thus, the minimum value of theta is confirmed to be 180º.
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Homework Statement



The 70N force acts on the end of the pipe at B. determine the angles theta between 0 and 180 of the force that will produce maximum and minimum moments about point A.

Homework Equations



FBD is attached.

The Attempt at a Solution



I made the following equation then took its derivative and put it equal to 0. The problem here is that I only get one value of theta. the one which gives the maximum value of the moment. there isn't any other value of tan coming withing 0-180. How do I get the minimum value of theta from this method. Wasn't I automatically supposed to get two value of theta from the first derivative and then I could I have gone further to second derivative to check if it was min or max. I am stuck.

Equation :- M = (70cos\theta * 0.9) + (70sin\theta * 0.7)
Derivative :- = -63sin\theta + 49cos\theta
 

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Altairs said:
I made the following equation then took its derivative and put it equal to 0. The problem here is that I only get one value of theta. the one which gives the maximum value of the moment. there isn't any other value of tan coming withing 0-180. How do I get the minimum value of theta from this method. Wasn't I automatically supposed to get two value of theta from the first derivative and then I could I have gone further to second derivative to check if it was min or max. I am stuck.

Equation :- M = (70cos\theta * 0.9) + (70sin\theta * 0.7)
Derivative :- = -63sin\theta + 49cos\theta

Hi Altairs! :smile:

(btw, I haven't seen the picture yet)

erm … sometimes it's maths, and sometimes it's just looking at the reality.

It often helps to draw a diagram (roughly).

The graph of the moment should look like a hill.

At 0º, the derivative is 49, which is positive; at 180º, it is -49, which is negative.

So the moment is already increasing at 0º, and is still decreasing at 180º.

So one of them may be a minimum … :smile:
 
Sorry. Can't get it. Would be easier with a few equations.
 
Hi Altairs! :smile:

(Still can't get the picture - I keep getting the please-log-in screen! :cry:)

At 0º, the moment is 63; it goes up until tantheta = 7/9; then it goes down until, at 180º, it is -63.

So the maximum is at tantheta = 7/9, them minimum is at 180º. :smile:
 

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