What Are the Possible Genotypes of the Bull and Cows in This Monohybrid Cross?

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The discussion centers on determining the genotypes of chickens and cows based on their offspring's traits. Chickens known as creepers, when crossed with normal birds, produce a 1:1 ratio of creepers to normals, suggesting the creeper trait is likely dominant. When creepers are mated with each other, a 2:1 ratio of creepers to normals indicates that one genotype is lethal. For the cows, all hornless offspring from a horned cow suggest that the hornless trait is recessive, leading to the conclusion that hornless cows must have the genotype HH. The analysis emphasizes the importance of understanding dominant and recessive traits in genetic crosses.
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Chickens with shortened wings and legs are called creepers, when creepers are mated to normal birds, they produce half creepers and half normal birds. When creepers aremated to creepers they produce 2 creepers to 1 normal. Crosses between normal birds produce only normal offspring. How must thesee results be explained?



Determine the geotypes of the bull and the 3 cwos. Hornless is recessive when Cow A is mated with the bull, the calves are all hornless. When cow B is mated with the bull the calvbes are all hornless. When cow C is mated with the bull a horned calf results. Cow A is horned. Cow B is hornless and Cow C is hornless



Thanks any help will be appreciated
 
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It is difficult to give hint without answering the question but here goes:

Call the creeper allel C and the normal one N, then a creeper may have genotype CN or CC, normal ones could be CN or NN. See what genoptypes the offspring would have assuming the different possible genotypes of the parents (you will have to assume that one genotype is letal in order to explain the "2 creeper 1 normal" frequency of the offspring of creepers corssed with creepers).


Call hornless allel H and the horns allel N, since hornless is recessive you know that all hornless cows must have genotype HH, using the results of the crossings you can easily figure out whether the others are HN or NN.
 
Karma, first figure out which trait is dominant and if the parent are heterozygous or homozygous


gerben said:
(you will have to assume that one genotype is letal in order to explain the "2 creeper 1 normal" frequency of the offspring of creepers corssed with creepers).

No you don't. Creeper is probably dominant and the parent are probably heterozygous
 
iansmith said:
No you don't. Creeper is probably dominant and the parent are probably heterozygous

but then you would get 3 creeper 1 normal (not 2:1)
 
My bad. Maybe I should avoid answering question right after I wake up.
 
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