What Are the Solutions to This Two-Block System Problem?

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    Law Motion
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Homework Help Overview

The problem involves a two-block system connected by a cord over frictionless planes, where participants are exploring the direction of movement, acceleration, and tension in the cords when the blocks are released from rest.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the blocks, particularly the tension and gravitational forces, and how they relate to the direction of movement. Some suggest guessing a direction for acceleration to facilitate solving the problem.

Discussion Status

There is ongoing exploration of the problem, with some participants providing guidance on how to approach determining the direction of acceleration and the forces involved. No consensus has been reached yet.

Contextual Notes

Participants express uncertainty about the direction of movement and the lack of attempted solutions, indicating a need for further clarification on the problem setup.

mayeh
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Homework Statement



two blocks CONNECTED by a cord over a frictionless planes, (for illus. see the fig. below) (a) which way will the system move when the blocks are released from rest?
(b)what is the acceleration of the blocks
(c)what is the tension in the cords?

<a href="http://www.imagevimage.com/gallery.php?entry=images/sa.JPG"><img src="http://www.imagevimage.com/thumbs/sa.JPG" border="0" alt="" /></a>

http://www.imagevimage.com/images/sa.JPG

Homework Equations





The Attempt at a Solution



I still don't have any attempted solutions since i can't figure out which direction will the system go.. pls help..

 
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Well, you can try finding the force applied by tension along the slope of the wedge, and then comparing with the force of gravity on the blocks along the slope. Since the string is the same, the tension along the string will be uniform.
 
mayeh said:
I still don't have any attempted solutions since i can't figure out which direction will the system go.. pls help..
You don't need to know the direction of the acceleration ahead of time. Just guess a direction, call the acceleration "a", and then solve for it. If it comes out positive, you guessed correctly; if negative, it's opposite to what you assumed.

(You can also figure out the direction by comparing the force pulling each mass down the plane.)
 
thanks! i'll try that..
 

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