What are the steps for solving a 2nd order differential equation?

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The discussion focuses on solving second-order differential equations, specifically the equation y'' + ay' + by = g(x). It establishes that if y1 is a solution to this equation, then for any non-zero constant k, the solution to y'' + ay' + by = kg(x) is ky1. Furthermore, it confirms that the general solution to a non-homogeneous linear ODE consists of the complementary function plus a particular integral, leading to the conclusion that the solution to y'' + ay' + by = 3g(x) is 3y1 + y2.

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Firstly, suppose y1 is a solution to y''+ay'+by=g(x). What then is a solution of y''+ay'+by=kg(x), where k is an arbitrary non-zero constant?

Secondly, note that a general solution to a non-homogenous linear ODE is its homogenous solution plus one particular solution to its nonhomogenous ODE.
 
solution to y''+ay'+by=kg(x) is ky1?

so the solution to y''+ay'+by=3g(x) is the complimentyery function + particular integral = 3y1 + y2?
 
That should be correct.
 
thanks!
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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