What are the temperatures of the evaporator and condenser?

Click For Summary
SUMMARY

The discussion focuses on calculating the temperatures of the evaporator and condenser in a vapor-compression refrigeration cycle using provided inlet and outlet pressures and temperatures. The condenser inlet pressure is 1164 kPa with an inlet temperature of 382.8 K, while the outlet pressure is 1102 kPa at 297.2 K. The evaporator inlet pressure is 290 kPa with an inlet temperature of 259.5 K, and the outlet pressure is 268 kPa at 280.5 K. The calculations for heat load are based on the change in enthalpy, confirming the approach of using inlet and outlet enthalpy values to determine the heat transfer rates.

PREREQUISITES
  • Understanding of vapor-compression refrigeration cycles
  • Knowledge of thermodynamic properties of refrigerants
  • Familiarity with enthalpy calculations
  • Ability to interpret pressure-temperature relationships in refrigeration systems
NEXT STEPS
  • Study the basic vapor-compression refrigeration equation in detail
  • Learn about the P-h diagram for refrigerants
  • Research methods for calculating enthalpy changes in refrigerants
  • Explore the impact of varying pressures on refrigeration efficiency
USEFUL FOR

Students studying thermodynamics, engineers working with refrigeration systems, and professionals involved in HVAC design and analysis will benefit from this discussion.

Zheng_
Messages
24
Reaction score
1

Homework Statement


By the data given below,
Condenser Inlet Pressure (P1/kPa) 1164
Condenser Inlet Temperature (T1/K) 382.8
Condenser Outlet Pressure (P2/kPa) 1102
Condenser Outlet Temperature (T2/K) 297.2
Evaporator Inlet Pressure (P3/kPa) 290
Evaporator Inlet Temperature (T3/K) 259.5
Evaporator Outlet Pressure (P4/kPa) 268
Evaporator Outlet Temperature (T4/K) 280.5
find the temperatures of the evaporator and condenser in this Vapor-compression refrigeration cycle.
The pressures are calculated in absolute pressure.

Homework Equations


Basic vapor-compression refrigeration equation.[/B]

The Attempt at a Solution


[/B] Tried to solve by using the Inlet and outlet enthalpy based on P-h cycle of the refrigerant
qe = h4-h3 qc = h2-h1
= 415.433 – 229.4556 =229.4556 – 480.9
= 185.978 kJ·kg-1 = -251.444 kJ·kg-1
not sure if it's correct...

 
Physics news on Phys.org
I think you are supposed to determine the change in enthalpy of the fluid between the inlet and outlet of the device to determine the heat load, based on the inlet and outlet temperatures they gave you. So, in my judgment, your approach is correct.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
1K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 8 ·
Replies
8
Views
6K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
11
Views
15K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K