What Determines the Current in an AC Circuit with a Light Bulb?

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The discussion centers on determining the current in an AC circuit with a light bulb when a voltage is first applied. The maximum voltage is given as 763 V at a frequency of 22 Hz, and the light bulb has a power rating of 17 W. For part a, the correct answer regarding the current when the voltage is first applied is 0, as this corresponds to time zero in the AC cycle. In part b, the user attempted to calculate the current at t = T/4 but incorrectly used average power instead of instantaneous power, leading to an incorrect answer. The key takeaway is that the average power should not be confused with instantaneous values in AC circuits.
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The current in the circuit ...??

Homework Statement



An AC voltage of the form V = Vmax sin 2*pi*f*t , with frequency 22 Hz and maximum voltage 763 V, is applied across a 17 W light bulb. When the voltage is first applied.

a) what is the current through the circuit?

Three Choices :

1. the maximum current
2. 0
3. the rms current

What is the correct answer and why ... ??


b) When t = T/4 , where T is the period of the applied voltage, what is the current in the circuit?



Homework Equations



P = I * V
I max = \sqrt{}2 * I rms
T = 1/f


The Attempt at a Solution



In part a) i think that when the voltage is first applied means that time is ZERO so it could be ZERO the options # 2

In part b) I substituted t = 0.25T or 0.25/f in this formual

V = Vmax sin 2*pi*f*t

I found V then I used P = I * V and solved for I but i got wrong answer.
 
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17 W is the average power over a full cycle. It's equal to I_{rms} V_{rms}. You used this value as if it was the instantaneous power at t=0.25T
 
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