What Determines the Number of Real Roots in a Quadratic Equation?

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Homework Help Overview

The discussion revolves around determining the conditions under which a quadratic equation has different types of real roots, specifically focusing on the equation px2 + qx + r = 0. Participants are exploring the use of the discriminant to identify these conditions.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the meaning of "state the condition" and is exploring the discriminant as a method to find the conditions for real roots. Some participants suggest that using the discriminant is a valid approach, while others provide specific conditions for different types of roots based on the discriminant's value.

Discussion Status

Participants are actively discussing the application of the discriminant to various quadratic equations. Some have provided guidance on how to set up the discriminant for different scenarios, while others are seeking clarification on specific cases involving variable coefficients.

Contextual Notes

There is mention of missing information due to a participant's absence from class, which may affect their understanding of the topic. Additionally, the discussion includes equations with variable coefficients, leading to questions about how to apply the discriminant effectively in these cases.

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Homework Statement


State the condition for the equation px^2 + qx + r = 0 to have:
a)two different real roots
b)two equal real roots
c)no real roots

Homework Equations


b^2-4ac maybe?

The Attempt at a Solution


I missed a class due to ailments and now have to catch up on missed work. I can't find what the question means by state the condition. All I need to know is what that even means, and maybe where to start working.

I've tried using the discriminant of the equation but I don't know what to do because the coefficients are variables, even the constant is a variable. Any help would be great, am I even on the right track with using discriminants?

I just tried using the discriminant of the equation with variables and for each a,b,c I came out with q^2-4pr > 0, q^2-4pr=0, q^2-4pr<0 respectively. I'm not sure if that is correct though.
 
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NO PROBLEM hyzon!
BY THE WAY WHAT YOU ARE THINKING IS CORRECT!YES THAT DISCRIMINANT WILL CERTAINLY HELP YOU & YOU ARE IN THE RIGHT WAY!
FOR ANY QUADRATIC EQUATION px2+qx+r=0
we have solution of x=(-q(+or-)squareroot(q2-4pr))/(2*p)
WELL IT IS MORE POPULAR AS b^2-4a*c.
a)for roots to be real we just want the term inside the root to be greater than or equal to zero.
=>b^2-4a*c>=0
OR HERE IN THIS CASE:
q^2-4pr>=0
=>q2>=4pr is the required condition for real roots.
IF THIS IS NOT SO THEN THE ROOT'S ARE NOT REAL AND ARE THUS IMAGINARY.
THUS a) AND c) ARE DONE.
b)HERE b^2-4ac=0 is condition for real roots.
=>q^2-4pr=0
=>q2=4pr is the required condition for equal roots.
 
Thanks, yeah so I get that now. But I'm stumped again on the same topic.

For what values of k does each equation have two different real roots?
a) x2+kx+1=0

I used the discriminant

k^2-4(1)(1)
k^2-4
k-2
k>2, k<(-2) or |k|>2

I understand that one, but question b) has k in the a position not b.

b)kx^2+4x-3=0

I put it in discriminant form

4^2-4(k)(-3)

Now what? How do I find the values of k to have two different real roots?
 
You use the condition discriminant > 0 like before, only it's a bit simpler to get k!
 

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