What Determines the Speed and Frequency of an Electron in a Magnetic Field?

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SUMMARY

The discussion focuses on calculating the speed, magnetic field, frequency, and period of an electron with a kinetic energy of 1.92 keV, orbiting in a magnetic field. The correct formula for speed is derived from the kinetic energy equation, leading to a speed of approximately 2.85E6 m/s, not 2.85E-23 m/s as initially calculated. The magnetic field can be determined using the formula B = mv/qR, where m is the mass of the electron, v is the speed, q is the charge, and R is the orbit radius. The frequency and period can be calculated using the relationships f = v/(2πR) and T = 1/f, respectively.

PREREQUISITES
  • Understanding of kinetic energy and its relation to speed
  • Familiarity with the mass and charge of an electron
  • Knowledge of magnetic fields and their effects on charged particles
  • Basic proficiency in algebra and physics equations
NEXT STEPS
  • Calculate the magnetic field using B = mv/qR
  • Determine the frequency of the electron's motion using f = v/(2πR)
  • Find the period of the motion with T = 1/f
  • Review the principles of circular motion in magnetic fields
USEFUL FOR

Physics students, educators, and anyone interested in the dynamics of charged particles in magnetic fields will benefit from this discussion.

missyc8
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Homework Statement



An electron with kinetic energy 1.92 keV circles in a plane perpendicular to a uniform magnetic field. The orbit radius is 26.0 cm.
Find the speed of the electron.

Find the magnetic field.

Find the frequency of circling. (Hz)

Find the period of the motion.


Homework Equations


v=sqrt(2*(3.7E-16J/9.109E-31)
k=(mv)^2/2
B-mvqr

The Attempt at a Solution


for velocity i get 2.85E-23 m/s ...but it is wrong...i do not know what to do
 
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missyc8 said:

The Attempt at a Solution


for velocity i get 2.85E-23 m/s ...but it is wrong...i do not know what to do

try computing sqrt(2*(3.7E-16J/9.109E-31)) again
 

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