A What do physicists mean when they say photons have a "path"?

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The discussion centers on the concept of "paths" in relation to photons and quantum mechanics, highlighting a common misconception. Some participants argue that photons do not have defined paths due to their quantum nature, particularly in the context of entanglement and experiments like the delayed-choice quantum erasure. Others counter that while photons lack a precise position observable, they can still be described as having paths based on experimental outcomes and the terminology used in scientific literature. The debate emphasizes the importance of understanding the distinction between classical and quantum descriptions of light, with references to the electromagnetic field and the probabilistic nature of photon detection. Ultimately, the conversation reflects differing interpretations of quantum mechanics and the semantics surrounding the term "path."
  • #31
vanhees71 said:
Which paper is this?

Oops, forgot to post the reference itself (this is a just one I picked out of the blue):

Kim et al, 2001
https://arxiv.org/abs/quant-ph/0103168
 
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  • #32
vanhees71 said:
1. It's simply impossible to describe these entangled photons in terms of trajectories (or paths) as you claim.

2. Parametric downconversion can only be understood in a QFT way (non-linear quantum optics).

3. Nobody denies that photons are "massless spin-one particles".
1. And yet I did, in detail, in post #32, to within a fraction of a wavelength. Talk to Tittel and explain it to him, then get back to me on that.

2. That's baloney, and you should know better. Conservation and basic QM is plenty enough to describe PDC as it relates to entanglement tests. And that is only one method of creating entanglement. Early experiments created entangled photon pairs using a Cesium cascade, no QFT required.

3. As I have said over and over again, photons are particles. They are quantum particles of course, and subject to "quantum" things like the uncertainty principle. Again, no QFT required.

----------------------------

To anyone still reading this thread: I've said everything that I can say, and have already repeated myself too much. I don't think there are any useful words left for me to say.

@vanhees71: It's to you to have the last word. I thank you for the scholarly discussion. Hopefully this thread will be closed soon.

-DrC
 
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  • #33
DrChinese said:
@PeterDonis ("saying I am not following generally accepted science")
Where have I said that? I explained in post #14 what particular claim I was objecting to.
 
  • #34
mattt said:
DrC, you are calling "a path" a collection of two ( or a finite number at most) of spatial points, whereas Peter Donis and Vanhees are calling "a path" something like a "continuous curve".

You both are right in your assertions (within your different meanings of "path").
@DrChinese, if all you mean by "path" is what is described above (two spatial points, which in the case of the experiment described in the OP, would be the exit point at the crystal and either detector A or detector B), then I agree that the photons in the experiment have a "path" in this sense (although I would not myself use the term "path" for this, but that's a matter of choice of words, not physics).

But then there was no need for you to bring in references to experiments using fiber optic cables, which led me to believe you meant "continuous curve" when you said "path"--otherwise those experiments would not even be relevant, since in the experiment in the OP there are no fiber optic cables, just free space between the exit of the crystal and either detector A or detector B.
 
  • #35
PeterDonis said:
@DrChinese, if all you mean by "path" is what is described above (two spatial points, which in the case of the experiment described in the OP, would be the exit point at the crystal and either detector A or detector B), then I agree that the photons in the experiment have a "path" in this sense (although I would not myself use the term "path" for this, but that's a matter of choice of words, not physics).

But then there was no need for you to bring in references to experiments using fiber optic cables, which led me to believe you meant "continuous curve" when you said "path"--otherwise those experiments would not even be relevant, since in the experiment in the OP there are no fiber optic cables, just free space between the exit of the crystal and either detector A or detector B.

Entangled photons travel on paths whether or not they are in fiber. They almost exactly follow classical trajectories. They are NOT classical paths however, for a lot of reasons. The main reason is that photons are quantum particles, not classical particles. I don't know if an individual photon travels on one path, many paths (path integral concept), different paths in different MWI worlds, exact Bohmian trajectories, are continuous or not, etc. They can do lots of things when not being observed. (Nobody I aware of on this planet has any superior understanding of the "truth" of what happens.)

And yet: every experimentalist does all test calibration as if they are observing entangled photons moving on their precisely desired "classical" path with a classically expected arrival time relative to the entangled partner. Let's just call that a path, like everyone else does. Life will be simpler and better.

If it looks like a duck, and quacks like a duck... :smile:
 
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  • #36
DrChinese said:
They almost exactly follow classical trajectories.
The above seems inconsistent with this:

DrChinese said:
They are NOT classical paths
The latter I would agree with; the former I would not. I don't see how both can be true (to be clear, I'm talking about the case where there are no fiber optic cables or other devices present, just free space between source and detector).

DrChinese said:
photons are quantum particles, not classical particles. I don't know if an individual photon travels on one path, many paths (path integral concept), different paths in different MWI worlds, exact Bohmian trajectories, are continuous or not, etc. They can do lots of things when not being observed. (Nobody I aware of on this planet has any superior understanding of the "truth" of what happens.)
I agree with all of this.

DrChinese said:
every experimentalist does all test calibration as if they are observing entangled photons moving on their precisely desired "classical" path with a classically expected arrival time relative to the entangled partner.
So what do you think justifies this, given the other statements quoted above?
 
  • #37
PeterDonis said:
what do you think justifies this, given the other statements quoted above?
Let me give an example of a possible justification to see if it helps: suppose I assume that a photon is released from my photon source at time ##t = 0##. Say the expectation value of the wavelength of photons from my source is ##\lambda##. I know the distance from the photon source to the parametric down conversion crystal, and I know the distances from the crystal to detectors A and B, where the pair of down converted photons will be detected (assuming this run of the experiment produces such a pair). Could I compute the probability amplitudes for detecting photons at A and B as a function of time, and show that those amplitudes were sharply peaked around a time ##t = T##, where ##T## is the classical light travel time over the sum of the relevant distances? Would the sharpness of the peak be a function of how large the distances were as compared to ##\lambda##? Has any such computation been done in the literature?
 
  • #38
Before saying that photons have or not have paths, one should first say what photon is.

So what is a photon? A state in the one-photon sector of the QED Hilbert space? A click in the photon detector? A pointlike object in the Bohmian inerpretation? Something else? If we first agree on that, I think it will be much easier to agree on existence or non-existence of photon paths.

There is no doubt that experimentalists measure something that they call photon paths. But also there is no doubt that theorists can describe those experiments without dealing with a notion of photon paths. So in a sense, both sides are right.
 
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  • #39
In double slits experiments, it is possible for classical-like paths of observed photons to be inferred/derived.
Unobserved photons don't appear to have classical-like paths.
 
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  • #40
DrChinese said:
Oops, forgot to post the reference itself (this is a just one I picked out of the blue):

Kim et al, 2001
https://arxiv.org/abs/quant-ph/0103168
As expected this paper uses the standard quantum (!) optics treatment of photons in terms of the quantized electromagnetic field. You claim one could describe parametric down conversion, entangled two-photon states and all that within the naive photon picture of 1905. IMO that's simply impossible, because these phenomena need the correct QFT treatment. That's what's in all introductory chapters of modern quantum-optics textbooks, you however don't seem to accept as valid sources.
 
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  • #41
vanhees71 said:
You claim one could describe parametric down conversion, entangled two-photon states and all that within the naive photon picture of 1905.

Wow, where did you get that? What I actually said: "Conservation [of momentum, etc.] and basic QM is plenty enough to describe PDC as it relates to entanglement tests."

You don't need to know how to build a car to drive one. That's an analogy! You don't need to know how non-linear crystals generate entangled photon pairs to perform a Bell test. Or answer a post question.
PeterDonis said:
Let me give an example of a possible justification to see if it helps: suppose I assume that a photon is released from my photon source at time ##t = 0##. Say the expectation value of the wavelength of photons from my source is ##\lambda##. I know the distance from the photon source to the parametric down conversion crystal, and I know the distances from the crystal to detectors A and B, where the pair of down converted photons will be detected (assuming this run of the experiment produces such a pair). Could I compute the probability amplitudes for detecting photons at A and B as a function of time, and show that those amplitudes were sharply peaked around a time ##t = T##, where ##T## is the classical light travel time over the sum of the relevant distances? Would the sharpness of the peak be a function of how large the distances were as compared to ##\lambda##? Has any such computation been done in the literature?

Why yes! That was essentially done in the reference - and quote - I placed in my post #12 in this thread. Note that the answer is expressed differently - it's expressed as the relative difference in the arrival times at the A and B detectors (labeled differently in the paper). That's because the pair creation time cannot be well constrained to an arbitrarily small time window. (After all, it's a quantum particle. :smile: ) But note that comparing the path length to the wavelength precision, it's about 12 billion to 1 in terms of the peak expectation values.

1. The meaning of the above: It is AS IF (even though it's not) each photon travels a path that is very very nearly a continuous classical path - and nothing else! To the extent that they DON'T travel such a continuous classical path: they do such similar things that they arrive extremely closely together.

2. Further, it should be obvious from comparing these results with other Bell tests with total path lengths on the order of a laboratory room (perhaps 2 meters as compared to 8 kilometers from city to city, a ratio of 1:4000) that there is no more "quantum discontinuous" action during their travel due to the total length traversed. If there were, the much longer travel time of the Tittel et al experiment would require a proportional larger coincidence window. But it doesn't.

3. The conclusion: to the extent that entangled photons do not travel in classical paths, it is not measurable as having any dependency on path length. Please do not quote me as saying entangled photons travel on classical paths, they are quantum particles and subject to quantum rules. But there is no clear measurable evidence that they don't travel on continuous paths with current experiments.

4. One of the great and easily understandable proofs that photons don't travel on a classical path is the one in which light is reflected from a mirror to a source that measures the intensity of reflected light. Let's call that amount i1. It is possible to place small etchings at precise spots AWAY FROM the primary reflection point such that some destructive quantum interference is eliminated (which should result in MORE transmitted light). Such spots are NOT in the classical path, but are in the quantum path. We measure the intensity with the etchings in place, and it is i2. If photons travel along classical paths, i1=i2. In actual experiments, i1<i2 - defying common "sense". I have not seen a reference where a similar setup used entangled photons as the light source, but I think that would be interesting. According to Kaur and Singh (2020): "Because of path revealing quantum entanglement of particles the single particle interference is suppressed." Would that mean that entangled photons wouldn't have something like i1<i2?
 
  • #42
DrChinese said:
That was essentially done in the reference - and quote - I placed in my post #12
First, that experiment uses fiber optic cables, which, as I've already noted, physically constrains the "path"; it's not the same as having free space between the source and the detector.

Second, I don't see how any calculation of the sort I described is made in the paper. The authors assert that the relative path lengths will affect the relative arrival times at the detectors in a particular way, but they don't calculate it. If they are relying on such a calculation done elsewhere in the literature, they don't give a reference to it. I'm wondering if there is any paper in the literature that actually calculates the probability of arrival at the detector as a function of time and shows that it is sharply peaked around the expected classical light travel time from the source given the classical path length, at least for path lengths that are large compared with the wavelength of the light.
 
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  • #43
DrChinese said:
One of the great and easily understandable proofs that photons don't travel on a classical path is the one in which light is reflected from a mirror to a source that measures the intensity of reflected light. Let's call that amount i1. It is possible to place small etchings at precise spots AWAY FROM the primary reflection point such that some destructive quantum interference is eliminated (which should result in MORE transmitted light). Such spots are NOT in the classical path, but are in the quantum path. We measure the intensity with the etchings in place, and it is i2. If photons travel along classical paths, i1=i2. In actual experiments, i1<i2 - defying common "sense".
Yes, IIRC these experiments were discussed by Feynman in his physics lectures, and also in the popular book of his "QED", where he gives them as an example of light not behaving classically.
 
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  • #44
PeterDonis said:
First, that experiment uses fiber optic cables, which, as I've already noted, physically constrains the "path"; it's not the same as having free space between the source and the detector.

Second, I don't see how any calculation of the sort I described is made in the paper. The authors assert that the relative path lengths will affect the relative arrival times at the detectors in a particular way, but they don't calculate it. If they are relying on such a calculation done elsewhere in the literature, they don't give a reference to it. I'm wondering if there is any paper in the literature that actually calculates the probability of arrival at the detector as a function of time and shows that it is sharply peaked around the expected classical light travel time from the source given the classical path length, at least for path lengths that are large compared with the wavelength of the light.

1. I don't think that would make any measurable difference at all (by not constraining the path using fiber). I don't have any relevant references that would answer that either way. That is what I was mentioning in my post #41, point 4. You'd need to do a specific experiment to discern either way.

2. I am not sure anyone if working like that. There must be a lot of tuning going on in these experiments. As the photons go through varying materials, the speed through that medium varies from others. I will keep my eyes open for anything that seems to calculate that. One of the problems being that the photon creation times are random.
 
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  • #45
I'm surprised by this tread and the position of DrChinese, I thought it was consensus that in general there is no such thing as a particle path in the usual interpretation of QM (no Bohmian mechanics or anything like that).

In a standard single particle, two-slit experiment, given the original position of the source and the position of the measurement when the particle hit the detector: (1) what method from QM can we use to define a path? I don't think it exists, but even if it exists, (2) how can we be experimentally sure that was the actual path taken by the particle?
 
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  • #46
andresB said:
I'm surprised by this tread and the position of DrChinese, I thought it was consensus that in general there is no such thing as a particle path in the usual interpretation of QM (no Bohmian mechanics or anything like that).

In a standard single particle, two-slit experiment, given the original position of the source and the position of the measurement when the particle hit the detector: (1) what method from QM can we use to define a path? I don't think it exists, but even if it exists, (2) how can we be experimentally sure that was the actual path taken by the particle?

Good point AndresB, I wouldn't always take this position. But these are entangled particles. They do not produce double slit interference.

But even in the double slit, with a normal photon, I would say it took a "path". Being a quantum particle, it did not take one specific path in an experiment designed to highlight this quantum behavior. I point out another such in post #41 above, point 4: where light does not take classical paths.

But in an instance where such properties can be neglected - which was the case in the thread where this originated - of course I would talk about a photon's path. Virtually all photons that arrive anywhere do so upon what is almost perfectly a classical path - that is easily demonstrated by blocking anywhere along the most likely path. Should we need factor in the effect of gravity on light when we discuss how light moves? I would not mention that gravity bends light when discussing photon path unless there are large objects involved. To recap my position (from another post of mine above):

Entangled photons travel on paths whether or not they are in fiber. They almost exactly follow classical trajectories. They are NOT classical paths however, for a lot of reasons. The main reason is that photons are quantum particles, not classical particles. I don't know if an individual photon travels on one path, many paths (path integral concept), different paths in different MWI worlds, exact Bohmian trajectories, are continuous or not, etc. They can do lots of things when not being observed. (Nobody I aware of on this planet has any superior understanding of the "truth" of what happens.)

And yet: every experimentalist does all test calibration as if they are observing entangled photons moving on their precisely desired "classical" path with a classically expected arrival time relative to the entangled partner. Let's just call that a path, like everyone else does.


Guess what? All of the above is also true about momentum, position, etc. of any quantum particle. And yet we use the words momentum and position to discuss such particles. Obviously, if I choose to place these attributes in superposition, those words can become meaningless. So I would say there is context to consider, just as when answering a question on any subject.
 
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  • #47
What exactly is the word photon supposed to refer to in this context? Is it just any state of the quantized EM field?
 
  • #48
DrChinese said:
And yet: every experimentalist does all test calibration as if they are observing entangled photons moving on their precisely desired "classical" path with a classically expected arrival time relative to the entangled partner. Let's just call that a path, like everyone else does.

Well, I agree that If we don't look too deep into it, if we don't try to zoom too much into the particle position over time, then we can use the word "path" without any danger. That is compatible with the fact that at the most fundamental level in (the standard interpretation of) QM, particles don't have trajectories.
 
  • #49
A tennis ball is a collection of quanta and is generally assumed to have a path whether it is observed or not. In practice, all attempts to derive a classical path are successful and virtually everyone assumes an unobserved tennis ball has a definite well-established path. In QM terms, the tennis ball 'path' is the average of many trajectories that peak and average out mostly around the classical 'path'. Thus I suggest that QM treatments put commas around 'path' while practical treatments treat the path in question without commas for all practical purposes. Theory meeting practice is the unresolved issue of single outcomes in QM.
For ultimate exactness and truthfullness with theory however, the path should always be denoted as 'path'.
 
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  • #50
DrChinese said:
One of the problems being that the photon creation times are random.
True, but since the arrival times at the detectors are recorded (within a fairly narrow window), one can just do the calculation in reverse and look at the amplitude for emission from the source as a function of time, given a detection within the known time window, and see if it is sharply peaked about the expected classical emission time given the total path length from source to detector.

The quantum optics literature might not have such a calculation, but that could be because earlier literature on QED more generally did a calculation something like this. Unfortunately I'm not familiar enough with the QED literature to know where to look.
 
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  • #51
DrChinese said:
Good point AndresB, I wouldn't always take this position. But these are entangled particles. They do not produce double slit interference.
It depends, of course, on the setup. Recently we have discussed a nice double-double-slit experiment with entangled photons, demonstrating the original EPR debate about entanglement in momentum/position space (open-access article):

Kaur, M., Singh, M. Quantum double-double-slit experiment with momentum entangled photons. Sci Rep 10, 11427 (2020). https://doi.org/10.1038/s41598-020-68181-1
DrChinese said:
But even in the double slit, with a normal photon, I would say it took a "path". Being a quantum particle, it did not take one specific path in an experiment designed to highlight this quantum behavior. I point out another such in post #41 above, point 4: where light does not take classical paths.
Come on! That's at the very fundamentals of all quantum theory that there is no classical path. You cannot understand the diffraction pattern in experiments like that with single particles nor single photons. It's fasterfully explained in the introductory chapter of the Feynman lectures vol. 3.
DrChinese said:
But in an instance where such properties can be neglected - which was the case in the thread where this originated - of course I would talk about a photon's path. Virtually all photons that arrive anywhere do so upon what is almost perfectly a classical path - that is easily demonstrated by blocking anywhere along the most likely path. Should we need factor in the effect of gravity on light when we discuss how light moves? I would not mention that gravity bends light when discussing photon path unless there are large objects involved. To recap my position (from another post of mine above):

Entangled photons travel on paths whether or not they are in fiber. They almost exactly follow classical trajectories. They are NOT classical paths however, for a lot of reasons. The main reason is that photons are quantum particles, not classical particles. I don't know if an individual photon travels on one path, many paths (path integral concept), different paths in different MWI worlds, exact Bohmian trajectories, are continuous or not, etc. They can do lots of things when not being observed. (Nobody I aware of on this planet has any superior understanding of the "truth" of what happens.)
Photons don't take paths in the sense of classical particles. The classical limit of the quantized electromagnetic field is not a point-particle theory but classical Maxwell theory. AFAIK there is no satisfactory Bohmian interpretation of relativistic QFT.
DrChinese said:
And yet: every experimentalist does all test calibration as if they are observing entangled photons moving on their precisely desired "classical" path with a classically expected arrival time relative to the entangled partner. Let's just call that a path, like everyone else does.
No! When taking the effort to use entangled photon pairs usually researchers are after quantum effects, where a classical particle picture is inapplicable. Particularly photons don't even have a position observable. All that is physical are detection probabilities at positions defined by the detector at times measured by a clock.
DrChinese said:
Guess what? All of the above is also true about momentum, position, etc. of any quantum particle. And yet we use the words momentum and position to discuss such particles. Obviously, if I choose to place these attributes in superposition, those words can become meaningless. So I would say there is context to consider, just as when answering a question on any subject.
For massive particles there exists a position observable, a non-relativistic approximation, and a classical point-particle limit, but not for photons. It is important to use the words "position" and "momentum" in the right way, when it comes to quantum properties of particles and photons, particularly in cases, which are not describable in terms of the classical point-particle picture, and particles or photons in entangled states are the extreme example for a situation, where the classical point-particle picture and even the classical theory of "local realism" a la EPR fails.

Parametric downconversion to prepare entangled photon pairs is also a characteristic example: The entanglement comes from the fact that you select such pairs via phase matching that you can't know in principle which "path" each of the photons took, and that's why you have a superposition that is not a product state, like the type-II case
$$|\Psi_{\pm} \rangle=\frac{1}{\sqrt{2}} [\hat{a}(\vec{k}_1,H) \hat{a}(\vec{k}_2,V) \pm \hat{a}(\vec{k}_1,V) \hat{a}(\vec{k}_2,H)]|\Omega \rangle.$$
As an example, see the paper with the theory about it you quoted yourself yesterday, where the state of the created pairs is treated in great detail including all the deviations from the above quoted idealized example:

https://arxiv.org/abs/quant-ph/0103168v1
 
  • #52
HomogenousCow said:
What exactly is the word photon supposed to refer to in this context? Is it just any state of the quantized EM field?
A photon is a single-photon Fock state by definition.
 
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  • #53
vanhees71 said:
AFAIK there is no satisfactory Bohmian interpretation of relativistic QFT.
Define "satisfactory"!

Certainly, there are versions of Bohmian relativistic QFT that make the same measurable predictions as standard relativistic QFT. If that's not satisfactory enough, then you should say what more do you expect from a satisfying theory.
 
  • #54
Is there a causal theory of classical point-particle trajectories?
 
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  • #55
vanhees71 said:
Is there a causal theory of classical point-particle trajectories?
Yes, it's called classical mechanics. But I think you meant something else. :wink:

Anyway, nobody said that Bohmian QFT must be about point-particles. There are versions of Bohmian QFT with fields instead of particles.
 
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  • #56
With respect to terms like “path“ in our language which is based on classical notions:

I deduce two general conclusions from these thought-experiments. First, statements about the past cannot in general be made in quantum-mechanical language. …. As a general rule, knowledge about the past can only be expressed in classical terms.

Freeman Dyson in „Thought Experiments in Honor of John Archibald Wheeler“ in “Science and Ultimate Reality”, Cambridge University Press, New York, 2004
 
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  • #57
vanhees71 said:
1. That's at the very fundamentals of all quantum theory that there is no classical path.

vanhees71 said:
2. You cannot understand the diffraction pattern in experiments like that with single particles nor single photons.

1. For the Nth time, read the words I write. I never said any photon takes a classical path. What I have said is:

a) Photons are quantum particles, demonstrate quantum observables, and do quantum things.
b) Entangled photons generally take a *near* classical path. They lack precise origin/creation times when created via PDC, which is what we were discussing.
c) The experimentalist, setting up a Bell test, acts as if it takes a classical path; and essentially ignores the contributions of paths outside of that as being grouped with the classical path.
d) There is nothing particularly different about the quantum nature of an entangled photon's path as compared to its momentum, wavelength, etc. A PDC entangled photon does not have a single well defined momentum or wavelength any more (or less) than it has a single well defined path. Yet we talk about photon momentum (you did anyway) and wavelength without feeling the need to consult a 664 page textbook when we discuss that.
e) Authors of scientific papers on the subject almost universally talk about photon path (or momentum, or wavelength), just as I did. Call it a "path" as it is commonly used in scientific writing. If it makes you feel better or it's more accurate: call it a "quantum path".

2. Importantly: the discussion topic was the entangled photons' paths labeled A and B. It had nothing to do with an experiment specifically designed to highlight quantum diffraction. Referring to entangled photon "path" makes perfect sense in this and most other contexts, just as you might refer to photon "wavelength".
 
  • #58
vanhees71 said:
A photon is a single-photon Fock state by definition.
Is that the kind of state that is produced by the sources in the experiments we have been discussing. My understanding is that the answer to that is "no": the sources in these experiments produce coherent states, not Fock states.
 
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  • #59
I think that's the central issue here, the typical coherent state produced by a classical source is not an eigenstate of particle number. In fact I suspect you can't make a spatially localized state without superimposing states with arbitrarily-high numbers of photons.
 
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  • #60
PeterDonis said:
Is that the kind of state that is produced by the sources in the experiments we have been discussing. My understanding is that the answer to that is "no": the sources in these experiments produce coherent states, not Fock states.
Parametric down conversion is today the standard method to produce true two-photon states,from which you can prepare proper single-photon states by using one of the photons in the pair to indicate that the other an only the other photon is there and not just a very dim coherent state.
 

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