What Do the Derivatives and Graphs Reveal About y=(2x+1)/\sqrt{x^2+1}?

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The discussion focuses on the function y=(2x+1)/√(x²+1) and its derivatives to analyze its behavior. The first derivative, dy/dx = (2x² - x + 2)/((x² + 1)√(x² + 1)), reveals that there are no roots, indicating the absence of vertical asymptotes since x² + 1 cannot equal zero. The analysis concludes that the function does not have horizontal asymptotes and suggests that the function either always increases or always decreases, as it lacks any horizontal line segments.

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Homework Statement



y=(2x+1)/\sqrt{x^2+1}

Find where are the asymptotes, where is it increasing increasing/decreasing, ect...

Homework Equations





The Attempt at a Solution


when I took the first derivative (im trying to find where it increases/decrease), I got
dy/dx = \frac{2x^2-x+2}{(x^2+1)\sqrt{x^2+1}}

but there isn't any roots for this function... so what does that mean?
 
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No vertical asymptotes as x^2+1 can never be 0.

No horizontal asy as (x^2)^1/2 is one, and 2x is one.

Slant asymptote is synthetic division (x^2+1)^(1/2) |2x+1

If there are no 0's then that means that the equation always increases or decreases.
 
grammar police: Better would be "either always increases or always decreases".


Any graph that does not have a horizontal line segment "always increases or decreases"!
 

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