What Do You Need to Understand About Kinematics to Solve Collision Problems?

  • Thread starter Thread starter phoizgood
  • Start date Start date
  • Tags Tags
    Kinematics
AI Thread Summary
Understanding kinematics is crucial for solving collision problems, particularly in visualizing the motion of two vehicles. In the scenario presented, Speedy Sue is driving at 30.0 m/s and must determine if she will collide with a van 155 m ahead, moving at 5.00 m/s, while decelerating at -2.00 m/s². The key to solving this problem lies in finding the condition for a collision, which occurs when the final positions of both vehicles are equal. Additionally, analyzing speed vs. time graphs helps in understanding the relationship between speed, time, and distance traveled, as the area under the graph represents distance. Ultimately, grasping these concepts will aid in determining whether a collision occurs and the specifics of the scenario.
phoizgood
Messages
3
Reaction score
0
I need help understanding this question. I don't need the answer or anything, I just want some help visualizing, what's going on, what do I need to know, how do I get there, etc. Am I being confusing?

Speedy Sue, driving at 30.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 155 m ahead traveling at 5.00 m/s. Sue applies her brakes but can accelerate only at -2.00 m/s^2 because the road is wet. Will there be a collision? If yes, determine how far into the tunnel and at what time the collision occurs. If no, determine the distance of cloest approach between Sue's car and the van.

Am I suppose to find when the two car is same distance or something?? Please help me.
 
Physics news on Phys.org
phoizgood said:
I need help understanding this question. I don't need the answer or anything, I just want some help visualizing, what's going on, what do I need to know, how do I get there, etc. Am I being confusing?

Speedy Sue, driving at 30.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 155 m ahead traveling at 5.00 m/s. Sue applies her brakes but can accelerate only at -2.00 m/s^2 because the road is wet. Will there be a collision? If yes, determine how far into the tunnel and at what time the collision occurs. If no, determine the distance of cloest approach between Sue's car and the van.

Am I suppose to find when the two car is same distance or something?? Please help me.
What is the condition for a collision?

If you plot speed vs. time for each vehicle, the area under the graph represents what quantity? Are those areas ever equal?

AM
 
"What is the condition for a collision?"

When the two car's X_final equals to each other? correct?

"If you plot speed vs. time for each vehicle, the area under the graph represents what quantity? Are those areas ever equal?"

speed vs time graph, area under graph is acceleration right? so what does having equal acceleration fits in this equation?

sorry for my bad english.
 
phoizgood said:
"What is the condition for a collision?"

When the two car's X_final equals to each other? correct?

Correct.

"If you plot speed vs. time for each vehicle, the area under the graph represents what quantity? Are those areas ever equal?"

speed vs time graph, area under graph is acceleration right?

No.

Without calculus:

Area=(length)(height)
On a speed vs time graph, length is time and height is speed.
What happens to the units when you multiply time by speed? What units do you end up with? What are those units used to measure?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top