What Does a CCD Pixel Measure?

  • Thread starter Thread starter blue_leaf77
  • Start date Start date
  • Tags Tags
    Ccd Pixel
AI Thread Summary
A CCD pixel measures the light intensity that is projected onto its surface area. When a plane wave of intensity I0 strikes the pixel at an angle α, the flux entering the pixel is calculated as F = I0 dx dy cos(α). The pixel's sensitivity is more accurately described by the projected intensity I0 cos(α), which represents the intensity per unit area. However, the pixel's effective area is still defined as dx dy, which is crucial for understanding the total light captured. Thus, the relationship between the intensity and the pixel area is essential for accurate measurement.
blue_leaf77
Science Advisor
Messages
2,637
Reaction score
786
I have a got a problem regarding what a CCD pixel actually measures. Suppose I have a pixel of area dx dy. A plane wave of intensity I0 is impinging on the pixel making an angle α with the normal of pixel surface. The flux going into the pixel would be F = I0 dx dy cos(α). My question what is the pixel directly sensitive to, is it F or I0 cos(α)?
 
Physics news on Phys.org
The I0 cos(a) is the intensity per unit area whereas your actual area is dx by dy. Right?
 
You can say so, but strictly speaking I0 cos(a) is the projection of intensity vector (or Poynting vector) to the normal of the pixel surface. The actual area is dx dy.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top