MHB What does normalized mean in this context?

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In the context of the paper, "normalized" refers to the process of calculating normalized interruption time (NIT) by dividing each user's viewed length by the original duration of the video. This approach accounts for the variability in how much of the video users actually watch. The discussion clarifies that NIT is not calculated by the sum of interruptions divided by non-interrupted times or total time watched, but rather by the entire duration of the video. The consensus is that normalization helps provide a more accurate metric for playback interruptions relative to the video's length. Understanding this concept is crucial for interpreting the author's findings effectively.
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In a paper I'm reading the author keeps using the word "normalized". What does it mean?
We use playback interruption time as our main metric.
However, since the viewed length by a user varies widely,
instead of just measuring total interruption time of each view,
we normalize it by the viewed length, which we call the
normalized interruption time (NIT).

Does it mean dividing the sum of the interuptions by the sum of the non-interrupted times? Or diving it by the total time thus far? Or dividing by the entire time of the video?
 
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It means diving each viewed length by the original duration of the video.
However, you must tell about the exact origin of this paragraph.
 
phymat said:
It means diving each viewed length by the original duration of the video.
However, you must tell about the exact origin of this paragraph.

Dividing by the entire duration of the video or up to the point watched?
 
find_the_fun said:
Dividing by the entire duration of the video or up to the point watched?

Usually it would mean dividing by the entire duration of the video.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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