What does the geodesic equation for a surface involve?

kleinwolf
Messages
293
Reaction score
0
I don't understand the equation of the geodesic y=y(x) for the surface given by z=f(x,y) :

a(x)y''(x)=b(x)y'(x)^3+c(x)y'(x)^2+d(x)dxdy-e(x)

the functions a,b,c,d,e are here not very important, what I don't understand, is that there is terms in \frac{dy}{dx} and dxdy...What does this mean ?
 
Physics news on Phys.org
Where did you get that equation...?It should come from the tensor one involving Christoffel symbols.

Daniel.
 
This is the equation in the special case where z=f(x,y)...the geodesics being given in the direct form : y=y(x)...I got this in Bronstein Taschenbuch der Mathematik.
 
I'm sorry,i can't get that book.Could u please indicate other source (it would be sizzling,if online) ?

Daniel.
 
Here is a scan :
 

Attachments

  • geod.jpg
    geod.jpg
    32.1 KB · Views: 464
It's a typo,i'm sure the German dude meant the derivative of the first order

\frac{dy}{dx}.

Daniel.
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...

Similar threads

Back
Top