What Does the Notation \(\frac{\partial u}{\partial t}(x,0)\) Indicate in PDEs?

  • Thread starter Thread starter yungman
  • Start date Start date
  • Tags Tags
    Notation Pde
yungman
Messages
5,741
Reaction score
294
What is the meaning of \;\;\frac{\partial u}{\partial t}(x,0)

Is it equal to \;\;\frac{\partial u(x,t)}{\partial t}\;\;first\;then\;set\;t=0

or \;\;\;\frac{\partial u(x,0)}{\partial t}\;\; Which is setting t=0 in u(x,t) first then differentiate?
 
Physics news on Phys.org
Well, if you set t=0 and then differentiate with respect to t, you're not going to get much...
 
Lord Crc said:
Well, if you set t=0 and then differentiate with respect to t, you're not going to get much...

Thanks

I just want to make double sure. Don't want to take anything for granted.
 
Good point :)
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...
Back
Top