What exactly is heat of combustion? How would I calculate it?

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SUMMARY

The heat of combustion for butane can be calculated using the provided mass of butane (0.15g) and the temperature change of water (from 16.4°C to 26.7°C). The reaction equation is 2C4H10 + 3O2 yields 8CO2 + 10H2O, which indicates that the heat of combustion is measured per mole of butane. To find the heat of combustion, one must first calculate the heat absorbed by the water using the formula q = mcΔT, where m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.

PREREQUISITES
  • Understanding of thermodynamics and calorimetry
  • Familiarity with the concept of heat transfer (q)
  • Knowledge of stoichiometry in chemical reactions
  • Basic skills in mole calculations and conversions
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  • Learn how to calculate heat transfer using q = mcΔT
  • Study the concept of enthalpy of combustion for different hydrocarbons
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Chemistry students, educators, and professionals involved in thermodynamics, particularly those focusing on combustion reactions and calorimetry techniques.

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1. Calculate heat of combustion for butane. Given:

mass water- 129.91g
mass butane 0.15g
old temp- 16.4 degrees C
new temp.- 26.7 degrees C

2. Homework Equations

2C4H10 + 3O2 yields 8CO2 + 10H2O

3. The Attempt at a Solution

I've tried, but I really have no idea. I only know how to calculate q and apparently that's not the same.
 
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Heat of combustion is per mole, what you have calculated is for 0.15g...
 

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