What exactly is this question acting?

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The discussion focuses on understanding the concept of domain in relation to the arcsin function. The domain of arcsin(x) is defined as the interval [-π/2, π/2]. It is clarified that since -1 is within this domain, arcsin(sin(-1)) equals -1. The participants confirm that the arcsin function serves as the inverse of the sin function within this specified domain. Overall, the conversation emphasizes the importance of recognizing the domain when evaluating inverse trigonometric functions.
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http://www.math.poly.edu/courses/ma0914/past_exams/MA922_Midterm_2001-05-23.pdf

The first questions that are asking about domain. If I recall right domain is the set which has all possible inputs for a function. I don't understand it means in this context.

Lol it wrote acting instead of asking.
 
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Hmm yeah that does look odd. I suppose what it's supposed to be trying to say is within the domain of arcsin(x), is the value of arcsin(sin(-1)) = -1?
 
Well then the answer would be yes because sin-1 is a number less then 1 and -1.
 
xdrgnh said:
Well then the answer would be yes because sin-1 is a number less then 1 and -1.

Nearly, the arcsin function is taken to be the inverse of the sin function on the domain x\in \left[-\frac{\pi}{2},\frac{\pi}{2}\right] and so because -1 is in this domain, then sin(-1) is defined and thus arcsin of that value is also defined, giving us back the value -1.
 
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