What Factors Determine the Maximum Allowable Force on a Wooden Beam?

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Homework Statement


Finding the maximum allowable force P before failure

Homework Equations


Shear /normal stress = Force / Area

The Attempt at a Solution


I know that I can resolve the force P to be along and normal to the end of the wooden beam to find the respective forces separately,applying factor of safety, from the failure stresses given and therefore, determine which P is lower which shall be the maximum allowable P. However, I do not see there the distance b come into play. Am i missing something?
 

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Can you show how you "resolved" P?
 
Pcos30 will be my shear force and Psin30 will be my normal force to the end of the beam.
 
Don't you mean P/2cos30 and P/2sin30?