What focal length is needed for a 0.60x magnification with a diverging lens?

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To achieve a magnification of 0.60x with a diverging lens for an object 1.40 meters away, the formula M = -di/do is applied, resulting in di being -0.84 meters. The lens formula 1/do + 1/di = 1/f is then used, leading to the calculation of the focal length f. The final calculation indicates that the required focal length is approximately 1.42 meters. There is a clarification regarding the sign convention in the calculations. The discussion emphasizes the importance of correctly interpreting the signs in lens equations.
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Homework Statement


What focus is needed for in order for a diverging lens to produce a magnification of 0.60x on an object located 1.40 meters away?

Homework Equations


M=hi/ho
1/do + 1/di = 1/f
M= -di/do

The Attempt at a Solution


-di / 1.4 = 0.6
1/1.4 + 1/.84 =1/f
-di=0.84
1.42
 
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Taylor Marks said:

Homework Statement


What focus is needed for in order for a diverging lens to produce a magnification of 0.60x on an object located 1.40 meters away?

Homework Equations


M=hi/ho
1/do + 1/di = 1/f
M= -di/do

The Attempt at a Solution


-di / 1.4 = 0.6
1/1.4 + 1/.84 =1/f
-di=0.84
1.42
Is that + sign correct?
 
Just a small remark - rather say what focal length is needed...
 
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