What happens/takes place in the molybdenum nucleus

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SUMMARY

The discussion centers on the decay process of Molybdenum-99 (Mo-99) into Technetium-99m (Tc-99m) through beta decay. In this process, one neutron in the Mo-99 nucleus, which consists of 42 protons and 57 neutrons, transforms into a proton by expelling an electron. This results in the formation of Tc-99m, characterized by 43 protons and 56 neutrons, which exists in a meta-stable state before decaying into stable Technetium-99 (Tc-99) by emitting a gamma ray photon. Tc-99m has a half-life of approximately 6 hours, while Tc-99 has a significantly longer half-life of over 210,000 years.

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Homework Statement
What happens/takes place in the molybdenum nucleus as it decays to Technetium-99 when a beta particle is emitted?
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This is not so much of a problem as I'm just interested If anyone knows what happens. It does relate to my homework problem tho because I had to write what Molybdenium decays into from beta which is Molybdenum-99/42Technetium-99m/43
 
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One of the neutrons in the Mo-99 nucleus (42 protons + 57 neutrons) expels an electron which results in the neutron becoming a proton. So the nucleus now has 43 protons and 56 neutrons and is now Technetium. What makes this nucleus so unusual is that the nucleus remains in an excited state for a while afterward, called a meta-stable state. This excited Technetium daughter nucleus is designated Tc-99m (the m signifying the meta-stable energy state). The Tc-99m nucleus will then decay by releasing a gamma ray photon (Tc-99m has a half-life of about 6 hours) and become fairly stable Tc-99 (half-life of over 210,000 years).

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