What Happens to Rotational Velocity When AC Part is Dropped?

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SUMMARY

The discussion centers on the effects of dropping a segment (AC) from a uniform rod rotating at 5 rad/s about an axis (PQ). The initial setup involves a rod with equal segments AO and OB, each measuring 4m. When the AC part is dropped, the remaining rod's rotational velocity must be recalculated by considering the angular momentum before and after the drop. The key challenge is determining the angular momentum of the dropped segment to accurately compute the new rotational velocity of the remaining rod.

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Anisur Rahman
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TL;DR
Need help in this question.
In figure AO = OB = 4m. C is the midpoint of AO. The rod rotates with a velocity of 5 rad/s about the axis PQ. What will be the rotational velocity of the remaining rod if AC part is suddenly dropped from the rod? Assume that the mass of this uniform rod is M.
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What do you think it will happen?
You will have less mass rotating, but not in a concentric way.
 
Lnewqban said:
What do you think it will happen?
You will have less mass rotating, but not in a concentric way.
To calculate the angular momentum of the remaining rod, I think to substract the angular momentum of the dropped part from primary angular momentum. But I am confused about to calculate the angular momentum of the dropped part. How can I calculate that?
 
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Anisur Rahman said:
TL;DR Summary: Need help in this question.

In figure AO = OB = 4m. C is the midpoint of AO. The rod rotates with a velocity of 5 rad/s about the axis PQ. What will be the rotational velocity of the remaining rod if AC part is suddenly dropped from the rod? Assume that the mass of this uniform rod is M.
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