What is a Vector: Sadri Hassani's Maths Physics Reading

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Vectors are defined abstractly in Sadri Hassani's "Reading in Mathematical Physics," highlighting their properties such as addition and scalar multiplication. Scalars, matrices, and tensors can all be considered types of vectors, with scalars being rank 0 tensors and vectors being rank 1 tensors. The discussion emphasizes that understanding vectors involves recognizing their transformation rules and the broader context of different metrics beyond Euclidean geometry. Additionally, it notes that elements of various mathematical structures, such as continuous functions, can also be viewed as vectors within their respective vector spaces. Overall, the conversation clarifies the foundational concepts of vectors and their relationships to other mathematical entities.
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Reading in Mathematical Physics by Sadri Hassani. It defines a vector abstractly. I will repeat that definition here rather more informally.

There are these things called vectors, a, b, x etc., that have these properties:

You can add them
a + b = b + a
a + (b + c) = (b + a) + c
a + 0 = a, 0 is the zero vector
a + (- a) = 0

You can multiply them by complex numbers (scalars) like c, d
c(d a) = (cd)a
1 a = a

Multiplication involving vectors and scalars is distributive
c(a + b) = c a+ c b
(c + d) a = c a+ d a

And that is it.

Given that definition, a scalar is a vector, a matrix is a vector, a tensor is a vector. Yes?

Mind you, I have also read that scalars and vectors are a kinds of tensors, of rank 0 and 1 respectively. True?

Am I confused? Should I be?
 
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tobor8man said:
Reading in Mathematical Physics by Sadri Hassani. It defines a vector abstractly. I will repeat that definition here rather more informally.

There are these things called vectors, a, b, x etc., that have these properties:

You can add them
a + b = b + a
a + (b + c) = (b + a) + c
a + 0 = a, 0 is the zero vector
a + (- a) = 0

You can multiply them by complex numbers (scalars) like c, d
c(d a) = (cd)a
1 a = a

Multiplication involving vectors and scalars is distributive
c(a + b) = c a+ c b
(c + d) a = c a+ d a

And that is it.

Given that definition, a scalar is a vector, a matrix is a vector, a tensor is a vector. Yes?

Mind you, I have also read that scalars and vectors are a kinds of tensors, of rank 0 and 1 respectively. True?

Am I confused? Should I be?

you shouldn't be confused... you'll learn that first) ther's not only euclidean geometry----> different metrics----> then a vector is a generalization of a tensor, you'l learn the meaning of covarianca and controvariance... and you'll understand that everything id defined by its tranformation rule...

say an euclidean vector V is something that |V|^2 is an invariant under SO(3) and that under rotation transform as: V'^{\mu}=R_{\mu\nu}V^{\nu} where R belongs to SO(3).
keep going...
regards
marco
 
A vector is an element of a vector space. Thus, elements of the real line are vectors if you endow the real line with the algebraic structure of a vector space. The set of all continuous functions over R is also a vector space, where the vectors are functions. Tensors with the usual addition are also elements of a vector space when regarded in that manner. This is a space where the vectors are tensors, and so forth.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

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