What is Coulomb potential and energy?

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Coulomb potential refers to the classical electrostatic potential that arises from the interaction between charged particles, primarily used in classical electrodynamics. The equations presented for potential V(r) and energy E may be misinterpreted; V is defined as V(r) = -Ze² / 4πεr, while energy E is given as E = Z²e² / 4πεr. The charge Q is correctly identified as Q = Ze, where Z is the number of protons, and the potential energy can be expressed as U = k(-e)(Ze)/R = -kZe²/R. Classical treatment of atoms is typically limited to one-electron systems, as multi-electron atoms introduce significant quantum effects that complicate the application of Coulomb's law. Understanding these distinctions is crucial for accurately describing atomic interactions.
quietrain
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is it just potential and potential energy?

but if so, why is it given as

V(r) = - Ze2 / 4πεr ?
and
E = Z2e2 / 4πεr

i am having trouble understanding how come for potential V, Q = Ze2

while

for E, Q2 = Z2e2

thanks!
 
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If E is meant to denote the classical electrostatic field and V the classical electrostatic potential, then your equations look all wrong. Where did you get them?

The term "Coulomb potential" is essentially used to mean the potential that gives rise to a classical electrostatic force (quantum effects can be neglected). Van der Waals force potentials, covalent bond potentials, quantum wells, etc. are all electromagnetic potentials but are quantum in nature.
 
i got them off my notes, but they may be wrong

so is it right that charge Q = Ze?

so electric potential energy = kQQ/R = k(Ze)2/R ?

Ze is bascially the charge of the nucleus right? number of proton mulitply by electron charge e?

also, so the term "coulomb" refers to classical electrodynamics mainly?
 
quietrain said:
i got them off my notes, but they may be wrong

so is it right that charge Q = Ze?

Yes, if you are neglecting screening and quantum effects, then the total charge of a mass it the number of elementary charges (protons) times the charge of one element.

quietrain said:
so electric potential energy = kQQ/R = k(Ze)2/R ?

I think I see the problem. Coulomb Potential energy U = kQ1Q2/R where Q1 is the charge of the one particle and Q2 is the charge of the other. If you are treating a one-electron atom classically, then for the electron Q1 = -e and for the protons, Q2 = +Ze so that:

U = k(-e)(Ze)/R = - k Ze2/R

quietrain said:
Ze is bascially the charge of the nucleus right? number of proton mulitply by electron charge e?
Yes
quietrain said:
also, so the term "coulomb" refers to classical electrodynamics mainly?

Yes
 
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chrisbaird said:
If you are treating a one-electron atom classically, then for the electron Q1 = -e and for the protons, Q2 = +Ze so that:

U = k(-e)(Ze)/R = - k Ze2/R

ah i see... but why is an atom "one-electron" classically?
 
quietrain said:
ah i see... but why is an atom "one-electron" classically?

When you have an atom with more than one electron, the quantum effects become so strong that using a classical approach is rendered essentially useless. If you are going to use Coulomb's law to describe an atom (already a shaky proposition), it's best to keep to one-electron atoms. Even with the help of quantum theory, deriving the potential of a multi-electron atom is nontrivial. Sadly, most of the atoms we encounter in every day life are multi-electron, so the clean one-electron pictures are not entirely useful.
 
i see thank you very much
 
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