What is ↔ mean? in commutation relation?

rar0308
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I found this in Srednicki's QFTbook.
I don't know what ↔ means.
Help me, please
 

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Presumably "the same term as before, but with the two indices exchanged". It should be deductible from the context, though.
 
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Yes, like that. (Except you forgot the i.) This is Eq (34.4) in Srednicki.
 
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