What is the acceleration and displacement of a ball rolling up and down a hill?

  • Thread starter Thread starter Carl_M
  • Start date Start date
  • Tags Tags
    Ball Hill
Click For Summary
SUMMARY

The discussion centers on calculating the acceleration and displacement of a ball rolling up and down a hill. The ball starts with an initial velocity of 4.00 m/s and, after 5 seconds, rolls down at 6.0 m/s. The acceleration can be determined using the change in velocity over time, while the displacement requires considering the initial velocity and the time of travel. The assumption of a constant hill angle allows for the application of gravitational components in the calculations.

PREREQUISITES
  • Basic physics concepts of motion, including velocity and acceleration
  • Understanding of gravitational forces and their components
  • Knowledge of kinematic equations for displacement
  • Familiarity with vector components in inclined planes
NEXT STEPS
  • Calculate acceleration using the formula: a = (final velocity - initial velocity) / time
  • Determine displacement using the kinematic equation: d = v_initial * t + 0.5 * a * t^2
  • Explore the effects of different angles of incline on acceleration and displacement
  • Investigate the role of friction in rolling motion on inclined planes
USEFUL FOR

Students studying physics, educators teaching motion dynamics, and anyone interested in understanding the principles of kinematics and gravitational effects on rolling objects.

Carl_M
Messages
13
Reaction score
0
A ball rolls at an initial velocity of 4.00 m/s up a hill. 5 seconds later it is rolling down the hill at 6.0 m/s. <---- What does the question mean? Did the ball roll up for 5 seconds and then started rolling down?

Find its acceleration
Find its displacement at 5.0s
 
Physics news on Phys.org
Assume it didn't start at the bottom - so it mght be doing 6.0m/s below where it started
 
So did the ball go up 4.00 m/s for 5 secs or go up the hill for 20 meters and then started to roll down at 6 m/s?
 
the ball will be decelarating due to gravity then begins rolling downhill at increasing speed

I think you could assume the hill is at a constant angle so the component of gravity causing the acceleration is constant at g.cos(theta) for whatever theta is...

you know a time and a change in velocity so you should be able to get to what that acceleration is ...
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
39
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 60 ·
3
Replies
60
Views
4K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
6K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
43
Views
4K