What is the acceleration of the elevator in these scenarios?

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SUMMARY

The discussion focuses on calculating the acceleration of an elevator based on the readings of a bathroom scale. When the elevator accelerates upward, the scale reads 919 N, indicating an upward acceleration of 9.29 m/s². Conversely, as the elevator approaches the 74th floor, the scale reads 782 N, resulting in a downward acceleration of -4.70 m/s². The calculations utilize Newton's second law (ƩF = ma) and the relationship between force, mass, and acceleration to derive these values.

PREREQUISITES
  • Understanding of Newton's second law (ƩF = ma)
  • Knowledge of gravitational force (9.8 m/s²)
  • Ability to calculate mass from weight (using weight = mass × gravity)
  • Familiarity with the concept of normal force in physics
NEXT STEPS
  • Study the application of Newton's second law in various scenarios
  • Learn about the concept of normal force and its role in different motion contexts
  • Explore the effects of acceleration on forces in non-inertial reference frames
  • Investigate real-world applications of elevator physics in engineering
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Students studying physics, particularly those focusing on mechanics, as well as educators teaching concepts related to forces and motion in elevators.

Ally385
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Homework Statement


A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. The scale reads 828 N.
(a) As the elevator moves up, the scale reading increases to 919 N. Find the acceleration of the elevator.
(b) As the elevator approaches the 74th floor, the scale reading drops to 782 N. What is the acceleration of the elevator?
(c) Using your results from parts a and b, select which change in velocity, starting or stopping, takes the longer time. Explain.

Homework Equations



f=ma

The Attempt at a Solution



I've done all of these problems twice and I can't figure out the solution. I thought you would just find the average acceleration but I guess not.
 
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Start by identifying the forces acting on the student, then apply Newton's 2nd law: ƩF = ma.
 


I know that the scale is exerting a force but I'm not sure how much. Also, would the elevator be exerting a force? I also know that gravity is a force but I think that's it.
 


Ally385 said:
I know that the scale is exerting a force but I'm not sure how much.
Right, the scale exerts an upward force. The force it exerts is the reading on the scale.
Also, would the elevator be exerting a force?
No, not directly. (It exerts its force by pushing on the scale. All we care about are forces on the person, and the scale is the only thing touching the person.)
I also know that gravity is a force but I think that's it.
Good. Only two forces act. Set up an equation from Newton's 2nd law, then you can solve for the acceleration.

Can you figure out the person's mass?
 


Ok so that would get you 828 N/ 9.8 m/s/s = 84.4898. Is that in kg? So that's the mass of the person so then do 919 N / 84.4898 = 10.88 which is your acceleration?

And then for the last part it would be 728/84.4898 = -8.62 the negative because it's slowing down. Negative acceleration. Correct?
 
Last edited:


I think it would be easier to use the difference in force 919- 828= 91 N. Since The 828 N was the weight of the person standing still, the 91 N must be the result of the upward acceleration of the elevator. NOW use "f= ma". What is m, the mass of the person?
 


Ok so acceleration would be 9.29 m/s/s and then for the second part it would be -4.70! I get it thank you :D
 


Ally385 said:
Ok so acceleration would be 9.29 m/s/s and then for the second part it would be -4.70! I get it thank you :D
You're off by a factor of 10. I suggest redoing them more carefully (especially the second part).

Don't skip steps. Write out the equation:
ƩF = ma
scale force - weight = ma
 
Elevator Standing Still: Normal Force (reading on scale)= Weight of person = mg
The Normal force required is enough to balance the downward force created by the mass (person) wanting to accelerate downward at 9.8 m/s/s. (the scale/floor of elevator prevents them from plummeting to their death)

Elevator accelerating upward: Normal force(reading on scale)= mg (for the same reasons as stated above) + ma. with "a" being upward acceleration of the mass (person) caused by the scale/elevator floor. (F=ma) since the force required to cause the upward acceleration opposes gravity, (just like the force required to prevent the person from plummeting to their death)

Elevator accelerating downward: same theory acceleration upward but since acceleration is in the same direction as gravity, it reduces the Normal Force required to keep the mass from plummeting. (you can subtract a positive value or add a negative value but either way, the Normal Force (reading on the scale) is reduced.
 

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