What Is the Angle of Inclination for a Car on a Banked Track?

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SUMMARY

The discussion focuses on calculating the angle of inclination for a car moving on a banked track. Given a car mass of 1000 kg traveling at a speed of 108 km/h (30 m/s) around a horizontal radius of 100 m, the angle of inclination can be determined using the formula tan(theta) = V²/(rg). Substituting the values, where g is the acceleration due to gravity (approximately 9.8 m/s²), the equation simplifies to theta = tan^-1(900/(100 x 9.8)).

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  • Understanding of basic physics concepts, particularly forces and motion.
  • Familiarity with trigonometric functions and their applications in physics.
  • Knowledge of the formula for centripetal acceleration.
  • Basic understanding of gravitational acceleration (g ≈ 9.8 m/s²).
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  • Study the derivation and applications of centripetal force in circular motion.
  • Learn about the effects of banking angles on vehicle dynamics.
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  • Investigate real-world applications of banked tracks in automotive and sports engineering.
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This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicles on curved paths.

chrisridgwell
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a car of mass 1000kg moves round a banked track at a constant speed of 108km/h. the reaction of the wheels is at right angles to the track, the horizontal radius is 100m. calculate the angle of inclination of the track.



Homework Equations


tan(theta)= V^2/rg



The Attempt at a Solution


108km/h = 30m/s
(theta)= Tan^-1(900/(100 x g))

im confused as to what g actually stands for
 
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chrisridgwell said:
im confused as to what g actually stands for
g is the acceleration due to gravity; g ≈ 9.8 m/s².
 
so the equation should read:
theta= tan^-1(900/(100x9.8))
 
Yes.
 
Thankyou very much, I am sure i will return
 

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