What is the Area of a Capacitor Plate?

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SUMMARY

The area of a capacitor plate can be calculated using the formula: plate area = (capacitance * distance) / (ε₀). In this discussion, the capacitance was determined to be 2 * 10^-8 F, and the distance between the plates was corrected to 0.90 * 10^-3 m. The final calculated area of the capacitor plate was found to be 2 m². This solution highlights the importance of unit conversion and direct calculation of area rather than relying on side length squared.

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  • Understanding of capacitance and its formula: capacitance = charge/volt
  • Familiarity with the permittivity of free space (ε₀) value: 8.85 * 10^-12 F/m
  • Knowledge of unit conversions, particularly between meters and millimeters
  • Basic algebra skills for manipulating equations
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  • Learn about the effects of plate separation on capacitance
  • Explore practical applications of capacitors in electronic circuits
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Homework Statement



platearea.jpg


Homework Equations


capacitance = charge/volt

capacitance = Esub0 (side of parallel plates^2)/(distance apart)

The Attempt at a Solution



capacitance = (3*10^-6 C)/(150v)
capacitance = 2 * 10 ^ - 8 F

2 * 10 ^ - 8 F = (8.85 * 10 ^ -12)(side of parallel plate) ^ 2/(.90 *10^-2)

side of parallel plate is 20 m ^ 2.
 
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warnexus said:

Homework Statement



platearea.jpg


Homework Equations


capacitance = charge/volt

capacitance = Esub0 (side of parallel plates^2)/(distance apart)




The Attempt at a Solution



capacitance = (3*10^-6 C)/(150v)
capacitance = 2 * 10 ^ - 8 F

2 * 10 ^ - 8 F = (8.85 * 10 ^ -12)(side of parallel plate) ^ 2/(.90 *10^-2)
Your distance value doesn't look right; check your units conversion. Since you're looking for the plate area anyways, why involve the square of the side length when you can solve directly for the area?

Fix your d value and try again. Make sure that your result description and units match (you reported a side length in square meters before).
 
gneill said:
Your distance value doesn't look right; check your units conversion. Since you're looking for the plate area anyways, why involve the square of the side length when you can solve directly for the area?

Fix your d value and try again. Make sure that your result description and units match (you reported a side length in square meters before).

oops milli is 10^ -3

i found my mistake. plate area = (capacitance)(distance)/(esub0)

plate area = (2*10^-8)(.90 * 10 ^-3)/ (8.85 * 10 ^ -12) = 2 m ^ 2 =]

thanks gneill
 
warnexus said:
oops milli is 10^ -3

i found my mistake. plate area = (capacitance)(distance)/(esub0)

plate area = (2*10^-8)(.90 * 10 ^-3)/ (8.85 * 10 ^ -12) = 2 m ^ 2 =]

Yup, that looks better :smile:
 

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