What Is the Capacitance of Three Concentric Spherical Shells?

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The discussion centers on calculating the capacitance of three concentric spherical shells with given charges and potentials. The capacitance formula C=Q/V is applied, where the potential difference is derived using Gauss's law. The user expresses uncertainty about how to incorporate the charges of all three shells, particularly when the inner and outer shells have the same potential. They propose using the difference in charges between the first two shells to find the capacitance, suggesting that this approach could be extended to include the third shell. The conversation highlights the complexities of capacitance in multi-shell configurations and the implications of potential differences.
MarkovMarakov
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Homework Statement


Hi, I would really appreciate clarification on the definition of capacitance in this context: Suppose I have 3 concentric metal spherical shells and they have charges Q1,Q2,Q3 and potentials 0,V,0 and radii a,b,c respectively, what is the capacitance of the configuration?


Homework Equations


C=Q/V


The Attempt at a Solution


I know what the capacitance is with only 2 spheres but I am not sure what it means with 3.
 
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Don't worry, I have figured it out! :)
 
I am inclined to answer although I am not 100% this solution is correct so please tell me if this is wrong.

As I'm sure your aware we calculate the capacitance for two concentric circles by
C=Q/V \; ,
where from Gauss's law we draw a sphere around the smallest shell.
V=\int_{a}^{b}E dr = \frac{Q_{enc}}{4 \pi \epsilon} \int_{a}^{b} r^{-2} dr =\frac{Q_{enc}}{4 \pi \epsilon} \left(\frac{1}{a}-\frac{1}{b} \right)
Since we are explicitly given the charges on each sphere, I believe the enclosed charge should be that of the innermost sphere. Now here is where I am stuck, the charge described in the capacitance equation refers normally to have a charge q and -q on each side, I am therefore going to assume that Q=abs(Q1-Q2)/2. This is probably wrong but I can't see any other way.
C_{a \rightarrow b}=\frac{2 \pi \epsilon |Q_{1}-Q_{2}|}{Q_{1}\left(\frac{1}{a}-\frac{1}{b} \right)}

This result holds in the three sphere setup since we only considered the enclosed charge (from Gauss). Therefore this could be easily extended for the third shell giving a second capacitance seen between b and c.

Hope that helps, and isn't completely wrong!
 
MarkovMarakov said:

Homework Statement


Hi, I would really appreciate clarification on the definition of capacitance in this context: Suppose I have 3 concentric metal spherical shells and they have charges Q1,Q2,Q3 and potentials 0,V,0 and radii a,b,c respectively, what is the capacitance of the configuration?


Homework Equations


C=Q/V


The Attempt at a Solution


I know what the capacitance is with only 2 spheres but I am not sure what it means with 3.

What is the implication if the inner and outer shells have the same ("zero") potential?
 

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