- #1
KhaNgo
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An electric field causes the 5.0 g point charge to hang at a 20 angle. What is the charge of the ball
I don't have the figure but it looks like a simple pendulum hanging at the angle of 20 degree
E= 100,000 N/C
m of the ball = 5g
Angle =20 degree
e0= 8.85*10^12
E = F (electrostatic) on p / p (charge)
F = (K q1 q2)/r12^2
q=E*r^2*4pi*e0
I have no clue
I don't have the figure but it looks like a simple pendulum hanging at the angle of 20 degree
Homework Statement
E= 100,000 N/C
m of the ball = 5g
Angle =20 degree
e0= 8.85*10^12
Homework Equations
E = F (electrostatic) on p / p (charge)
F = (K q1 q2)/r12^2
q=E*r^2*4pi*e0
The Attempt at a Solution
I have no clue